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KATRIN_1 [288]
3 years ago
15

The starting and stopping point for Amir’s run this morning are 0.5 inch apart on the map. If each inch on the map represents 3

miles, how far did Amir run?
Mathematics
2 answers:
Aleonysh [2.5K]3 years ago
7 0
Amir ran 1.5 miles in the morning.
loris [4]3 years ago
5 0

Answer:

1.5 miles.

Step-by-step explanation:

We have been given that starting and stopping point for Amir’s run this morning are 0.5 inch apart on the map. We are also told that each inch on the map represents 3 miles.

To find distance covered by Amir, we will use proportions as:

\frac{\text{Actual distance}}{\text{Map distance}}=\frac{\text{3 miles}}{\text{1 inch}}

\frac{\text{Actual distance}}{\text{0.5 inch}}=\frac{\text{3 miles}}{\text{1 inch}}

\frac{\text{Actual distance}}{\text{0.5 inch}}*\text{0.5 inch}=\frac{\text{3 miles}}{\text{1 inch}}*\text{0.5 inch}

\text{Actual distance}=\text{3 miles}*0.5

\text{Actual distance}=\text{1.5 miles}

Therefore, Amir ran a distance of 1.5 miles.

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GarryVolchara [31]

Answer:

The missing statement is ∠ACB ≅ ∠ECD

Step-by-step explanation:

Given two lines segment AC and BD bisect each other at C.

We have to prove that ΔACB ≅ ΔECD

In triangle ACB and ECD

AC=CE    (Given)

BC=CD   (Given)

Now to prove above two triangles congruent we need one more side or angle

so, as seen in options the angle ∠ACB ≅ ∠ECD due to vertically opposite angles

hence, the missing statement is ∠ACB ≅ ∠ECD


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3 years ago
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Answer:

\frac{(6p+14)}{p}

Step-by-step explanation:

(p+\frac{7}{3})(\frac{6}{p})

Making denominator same in first bracket we get

(\frac{3p+7}{3})(\frac{6}{p})

(\frac{(3p+7)*6}{3*p})

Dividing 6 by 3 we get 2

(\frac{(3p+7)*2}{p})

using distributive law

(\frac{6p+14}{p})\\

Hence this is our answer

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tamaranim1 [39]

Answer:

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Step-by-step explanation:

To evaluate f(7) substitute t = 7 into f(t)

f(7) = 3(7)² + 11 = (3 × 49) + 11 = 147 + 11 = 158

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322.28

A

Step-by-step explanation:

Area of the rectangle

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Area = 30 * 21

Area = 630

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Area = 3.14 * 7^2

Area = 153.86 m^2

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Area of the Shaded Region

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Area of Shaded Region = 322.28

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Answer:

5/143

Step-by-step explanation:

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