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2 years ago

PLEASE I’LL GIVE BRAINLIEST !!!!Complete the mapping of the vertices of ADEF.

Mathematics

1 answer:

alisha [4.7K]2 years ago

5 0

D'=(-4,2)
E'=(-1,1)
F'=(1,5)

Hope it heled.

Please note this rotation just allows you to turn (x,y) to (y,x)

Here are the rotation rules: 90° clockwise rotation: (x,y) becomes (y,-x) 90° counterclockwise rotation: (x,y) becomes (-y,x) 180° clockwise and counterclockwise rotation: (x, y) becomes (-x,-y)

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What is the value of log5 125?

zhenek [66]

$\rm log_{5}(125) \\ \rm log_{5}( {5}^{3} ) \\ \rm1 \cdot3 \\ 3 \\ \therefore \tt log_{5}(125) = 3$

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2 years ago

If a > b > c > d, then which is larger, a+c or b+d ? Can we tell from a > b > c > d which of a+d and b+c is la

victus00 [196]

Answer:

1. a+c is larger than b+d

2. No way to tell whether a+d or b+c is larger.

Step-by-step explanation:

1. Which is larger, a+c or b+d?

Let a, b, c, and d be any numbers such that $a > b > c > d$ .

Specifically, note that $a > b$ , and subtracting b from both sides of the inequality, observe that $a-b > 0$ .

Similarly, $c > d$ , and subtracting d from both sides of the inequality, observe that $c-d > 0$ .

From this, add "a-b" (a positive number, as proven above) to both sides of the inequality.

$(a-b)+(c-d) > (a-b)+0$

Addition by zero (the additive identity) doesn't change anything, so the right side remains "a-b"...

$(a-b)+(c-d) > a-b$

... and "a-b" is positive...

$(a-b)+(c-d) > a-b > 0$

... so, by the transitive property of inequality...

$(a-b)+(c-d) > 0$

Recall that subtraction is addition by a negative number...
$a+(-b)+c+(-d) > 0$

...and that addition is associative and commutative, so things can be added in any order, so the middle two terms on the left side can be rearranged...

$a+c+(-b)+(-d) > 0$

Adding b + d to both sides of the inequality

$(a+c+(-b)+(-d))+(b+d) > 0+(b+d)$

... and simplifying

$a+c > b+d$

So, a+c is larger than b+d.

2. Which is larger, a+d or b+c?

Consider the following two examples:

Example 1

Suppose a=10; b=3; c=2; d=1.

Note that $a > b > c > d$ ( $10 > 3 > 2 > 1$ ) and, also observe that $a+d=(10)+(1)=11$ , and $b+c=(3)+(2)=5$ , so a+d is larger than b+c.

Example 2

However, suppose a=10; b=9; c=8; d=1.

Note that $a > b > c > d$ ( $10 > 9 > 8 > 1$ ) but that $a+d=(10)+(1)=11$ , and $b+c=(9)+(8)=17$ , so a+d is smaller than b+c.

So, in one example, a+d is bigger, and in the other, a+d is smaller. Therefore, there is no way to tell which of a+d or b+c is larger from only the given information.

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2 years ago

8-5b=-7 solve please

lisov135 [29]

Answer:

Step-by-step explanation:

subtract 8

-5b=-15

divide negative 5

b=3

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3 years ago

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Jose invested $5000 into a fund with an interest rate of 4.8%.

Ann [662]

He will earn $480 after 2 years

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3 years ago

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PLEASE HELP ME

BigorU [14]

The coordinates of the image after a rotation 90° clockwise about the origin and then a dilation with a scale factor of 3 are: (3, -3), (12, -9), and (3, -15).

<h3>What is a rotation?</h3>

In Mathematics, rotating a point 90° about the origin in a clockwise or counterclockwise direction would produce a point that has these coordinates (y, -x).

By applying a rotation of 90° clockwise to triangle JKL, the coordinate of the image of triangle J'K'L' is given by:

(x, y) → (y, -x)

Points at J = (1, 1) → Points at J' = (1, -(1)) = (1, -1)

Points at K = (3, 4) → Points at K' = (4, -(3)) = (4, -3).

Points at L = (5, 1) → Points at L' = (1, -(5)) = (1, -5).

Next, we would dilate triangle JKL by multiplying with a scale factor of 3:

Points at J' = (1 × 3, -1 × 3) = (3, -3)

Points at K' = (4 × 3, -3 × 3) = (12, -9)

Points at L' = (1 × 3, -5 × 3) = (3, -15)

Read more on rotation here: brainly.com/question/28515054

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1 year ago