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rosijanka [135]
3 years ago
8

Help on logarithmic equation

Mathematics
1 answer:
inessss [21]3 years ago
8 0
\log _{ 2 }{ \left( 3-x \right)  } +\log _{ 2 }{ 5 } =2\log _{ 3 }{ 5 } \\ \\ \log _{ 2 }{ \left( 5\left( 3-x \right)  \right)  } =\log _{ 3 }{ \left( { 5 }^{ 2 } \right)  } \\ \\ { 2 }^{ \log _{ 3 }{ 25 }  }=5\left( 3-x \right) \\ \\ { 2 }^{ \log _{ 3 }{ 25 }  }=15-5x\\ \\ 5x=15-{ 2 }^{ \log _{ 3 }{ 25 }  }\\ \\ x=\frac { 15 }{ 5 } -\frac { { 2 }^{ \log _{ 3 }{ 25 }  } }{ 5 } \\ \\ x=3-\frac { { 2 }^{ \log _{ 3 }{ 25 }  } }{ 5 }
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Marta_Voda [28]

Based on the information given the chocolates stated on the label is 0.0042-ounce lighter.

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Using this formula

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Where:

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