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Naddika [18.5K]
3 years ago
8

Your assigned 32 math exercises for homework you complete 87.5of these before dinner how many do you hav to do after dinner.

Mathematics
1 answer:
krek1111 [17]3 years ago
5 0
87.5% of 32 questions = 28 questions.

32 - 28 = 4

so there are 4 questions to be done after dinner.
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(2t^(3)+3t-4)-(4t^(2)-6t)
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The function f(x) is represented by the table below. What are the corresponding values of g(x) for the transformation g(x) = 6f(
g100num [7]

Answer:

Given: The transformation g(x) =6f(x)                  ......[1]

To find the corresponding values of g(x) for the given transformation.

At x = -7, f(x) = 8

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By substituting the value of f(x) = 8 in [1] we have

g(x) = 6 \cdot 8 =48

Similarly,

For x= -3 , f(x) = 3, then

By substituting the value of f(x) = 3 in [1] we have

g(x) = 6 \cdot 3 =18

For x= 0, f(x) = -1 , then

By substituting the value of f(x) = -1 in [1] we have

g(x) = 6 \cdot -1 =-6

For x= 2, f(x) = 7, then

By substituting the value of f(x) = 7 in [1] we have

g(x) = 6 \cdot 7=42

For x= 10, f(x) = 5, then

By substituting the value of f(x) = 5 in [1] we have

g(x) = 6 \cdot 5=30

Therefore ; we have the corresponding values of g(x) as shown below;

x                f(x)           g(x)

-7                8                48

-3                3                 18

0                -1               -6

2                 7                42

10                5                30

5 0
4 years ago
Read 2 more answers
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choli [55]
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7 0
3 years ago
Select the most accurate statement regarding the normal distribution. Group of answer choices It is always the appropriate distr
PSYCHO15rus [73]

Answer:

There is a 95% chance that values will be within ±2 standard deviations of the mean.

Step-by-step explanation:

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Problems of normal distributions can be solved using the z-score formula.

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Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this question:

According to the empirical rule, 95% of the measures are within 2 standard deviations of the mean. So the correct statement is:

There is a 95% chance that values will be within ±2 standard deviations of the mean.

4 0
3 years ago
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