Dical and exponent What is 6 in radical form?

1 answer:

6 0

The square root pf a number can be simplified only if the number is divisible by a perfect square (other than 1).
√
12
can be simplified because
12
is divisible by
4
-- a perfect square.
√
12
=
√
4
×
3
=
√
4
×
√
3
=
2
√
3
√
250
can be simplified because
250
is divisible by
25

√
250
=
√
25
×
10
=
√
25
×
√
10
=
5
√
10
But
6
is not divisible by a perfect square, so
√
6
cannt be simpified further.

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If alpha and beta are the zeroes of the polynomial 6x2+x-2 find the value og alpha/beta + beta/alpha

castortr0y [4]

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$use\ Vieta's\ formula:\\\\\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{\alpha^2+\beta^2}{\alpha\beta}=\frac{\alpha^2+2\alpha\beta+\beta^2-2\alpha\beta}{\alpha\beta}=\frac{(\alpha+\beta)^2-2\alpha\beta}{\alpha\beta}=\frac{(\alpha+\beta)^2}{\alpha\beta}-2\\\\\alpha+\beta=\frac{-b}{a};\ \alpha\beta=\frac{c}{a}\\\\\frac{(\alpha+\beta)^2}{\alpha\beta}-2=\frac{\left(\frac{-b}{a}\right)^2}{\frac{c}{a}}-2=\frac{b^2}{a^2}\cdot\frac{a}{c}-2=\frac{b^2}{ac}-2$

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