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2 years ago

5

Consider the equation x/3+7=13.

1 answer:

Darya [45]2 years ago

5 0

Answer:

Step-by-step explanation:x/3+7=13

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Choose as many answers as apply.

suter [353]

All of them can be accomplished with electronic banking, but C and D would be easiest to do online.

3 0

2 years ago

Read 2 more answers

Solve the following differential equation: (1− 5 y +x) dy/dx +y= 5/x −1 .<br><br> C=

Ganezh [65]

Answer:

$y(1+x)+x-5\ln xy=C$

Step-by-step explanation:

Consider the given differential equation is

$(1-\frac{5}{y}+x)\frac{dy}{dx}+y=\frac{5}{x}-1$

$(1-\frac{5}{y}+x)\frac{dy}{dx}=\frac{5}{x}-1-y$

$(1-\frac{5}{y}+x)dy=(\frac{5}{x}-1-y)dx$

Taking all variables on right sides.

$(1-\frac{5}{y}+x)dy-(\frac{5}{x}-1-y)dx=0$

$(-\frac{5}{x}+1+y)dx+(1-\frac{5}{y}+x)dy=0$

Let as assume,

$M=-\frac{5}{x}+1+y$ and $N=1-\frac{5}{y}+x$

Find partial derivatives $\frac{\partial M}{\partial y}$ and $\frac{\partial N}{\partial x}$

$\frac{\partial M}{\partial y}=1$ and $\frac{\partial N}{\partial x}=1$

Since $\frac{\partial M}{\partial y}=\frac{\partial N}{\partial x}$ , therefore the given differential equation is exact.

The solution of the exact differential equation is

$\int Mdx+\int N(\text{without x)}dy=C$

$\int (-\frac{5}{x}+1+y)dx+\int (1-\frac{5}{y})dy=C$

$yx-5\ln x+x+y-5\ln y=C$

$y+x+xy-5\ln x-5\ln y=C$

$y(1+x)+x-5(\ln x+\ln y)=C$

$y(1+x)+x-5\ln xy=C$

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2 years ago

Veronica is choosing between two health clubs. After how many months will the total cost for each health club be the same? Yoga

Rina8888 [55]

Answer:

4 months

Step-by-step explanation:

8 0

2 years ago

faust18 [17]

Are you sure the options are what u have written above? because sqrt of 5x=sqrt of 5x,
sqrt of 20x=2•sqrt of 5x,and sqrt of 80x= 4•sqrt of 5x..

4 0

2 years ago

How many solutions does this system have? y = 3 x minus 5. y = negative x + 4. one two an infinite number no solution

AveGali [126]

Answer:

One

Step-by-step explanation:

It is given that,

y = 3x-5 ....(1)

y = -x+4 .....(2)

We can solve the above equations using substitution method. Put the value of y from equation (1) to equation (2) such that,

$3x-5 = -x+4\\\\3x+x = 5+4\\\\4x = 9\\\\x=\dfrac{9}{4}$

Put the value of x in equation (1) we get :

$y = 3x-5\\\\y = 3\times \dfrac{9}{4}-5\\\\y=\dfrac{7}{4}$

It means that the value of x is $\dfrac{9}{4}$ and the value of y is $\dfrac{7}{4}$ . Hence, the given equations has only one solution.

6 0

2 years ago