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Andre45 [30]
3 years ago
8

HELP ME OUT PLS !!!! THIS IS EASY

Mathematics
1 answer:
MakcuM [25]3 years ago
4 0

Answer:

C) 123 cm^2

Step-by-step explanation:

well if we find CD we can cut striat down C and do area of a triangle plus the area of the rectangle.

to find CD you need length of BC

BC^2 = AC^2-AB^2 --> BC^2 = 400-100 --> BC^2 = 300

BC = 300^2 --> about 17 causeing CD being 4

now we have info

triangle area is BxHx 1/2 --> 17x10x1/2 --> 85cm^2

Now we do the small rectangle area is BxH --> 4x10 --> 40cm^2

85 + 40 = 125cm^2

the only one close is 123cm^2

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Can you simplify am • an. if so what is it
Inga [223]

Answer:

Yes a^2mn

Step-by-step explanation:

You do this by multiplication.

6 0
3 years ago
The position function of a particle in rectilinear motion is given by s(t) = 2t^3 + 21t^2 + 60t + 3 for t ≥ 0 with t measured in
natta225 [31]
As the fellow above said, the particle does make a U-turn at the vertex, and we can find that out by getting the derivative of s(t) and zeroing it out to get the point of the horizontal tangent.

Bearing in mind that ds/dt is really v(t) or the velocity equation, so when we zero out the ds/dt, is the same as saying the velocity went to 0, since it got zeroed out, and then the particle goes over the vertex and changes direction.

\bf s(t)=2t^3-21t^2+60t+3\implies \boxed{\cfrac{ds}{dt}=6t^2-42t+60}\leftarrow v(t)
\\\\\\
0=6t^2-42t+60\implies 0=t^2-7t+10\implies 0=(t-5)(t-2)
\\\\\\
t=
\begin{cases}
5\\
2
\end{cases}\impliedby \textit{it makes the first turn at the \underline{2 second}}
\\\\\\
\textit{now let's find the acceleration equation, a(t)}
\\\\\\
\boxed{\cfrac{d^2s}{dt^2}=12t-42}\leftarrow a(t)\\\\
-------------------------------\\\\
s(2)=55\qquad \qquad \qquad \qquad a(2)=-18

the negative acceleration value, simply means a decreasing rate of change, so, it means the particle is slowing down and possibly coming to a stop before changing direction again.
8 0
3 years ago
A house is built on coordinates (2,9). There is a water pipeline that runs along the line y = 2 3 x – 1. What is the approximate
Basile [38]

Answer:

7.21 units

Step-by-step explanation:

The shortest length needed to connect the house to the existing pipeline is the perpendicular distance between the location of the house (2,9) and the line y = 2/3x - 1.

The perpendicular distance (d) between a point (x_1,y_1) and the line Ax + By + C  = 0 is given as:

d=\frac{|Ax_1+By_1+C|}{\sqrt{A^2+B^2} }

The line is given by y = 2/3 x - 1; 2/3x - y - 1 = 0. The point = (2, 9)

hence A = 2/3, B = -1, C = -1, x_1=2,y_1=9\\. Therefore:

d=\frac{|\frac{2}{3}(2)+(-1)(9)+(-1) |}{\sqrt{\frac{2}{3}^2+(-1)^2 } } \\\\d=7.21

4 0
3 years ago
PLEASE HELP ILL GIVE BRAINLIEST
IgorLugansk [536]

Answer:

3.7m/s^2

Step-by-step explanation:

T is given as 3.27 seconds

L= 1m

we have to find g just put values in given formula

3.27s=2pi(sqrt(1m/g))

3.27s/2pi=(sqrt(1m/g))

0.520s=(sqrt(1m/g))

Taking square on both side to eliminate square root

0.27085s^2=1m/g

Multiply with g on both sides

0.27085 s^2*g=1m

Divide both sides with 0.27085

g=1m/0.27085s^2

g=3.7m/s^2

6 0
4 years ago
Find the volume between the cone<br> X= sqrt(y^2 + z^2) and the sphere<br> x^2 + y^2 + z^2 = 16.
Luda [366]
Here is how to solve it

7 0
3 years ago
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