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4 years ago

-2/33/5+5/2-3/51/6

Mathematics

1 answer:

Kipish [7]4 years ago

3 0

Answer:

2and19/90

Step-by-step explanation:

-2/3*3/5= _2/5

-2/5+5/2-(2/3×1/6)

-2/5+5/2-1/9

21/10-1/9

=199/90

=2/19/90

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Van someone help me with this

gizmo_the_mogwai [7]

Answer:

107

Step-by-step explanation:

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3 years ago

Divide. −1/9÷3/4 −4/27 −1/12 1/12 4/27 PLZZZZ HELP FAST!

ivanzaharov [21]

$\frac{ - 1}{9} \div \frac{3}{4} \\ \\ \frac{ - 1}{9} \times \frac{4}{3} \\ \\ \frac{( - 1) \times 4}{9 \times 3} \\ \\ \frac{ - 4}{27}$

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3 years ago

Y varies directly with x and y=8 when x=-5

ale4655 [162]

Answer:

Y=K×X...... equation

When,Y=8 and X=-5

To find the constant (K)

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7 0

3 years ago

When the sum of \, 528 \, and three times a positive number is subtracted from the square of the number, the result is \, 120. F

aleksandr82 [10.1K]

Let $x$ be the unknown number. So, three times that number means $3x$ , and the square of the number is $x^2$

We have to sum 528 and three times the number, so we have $528+3x$

Then, we have to subtract this number from $x^2$ , so we have

$x^2-(3x+528)$

The result is 120, so the equation is

$x^2 - 3x - 528 = 120 \iff x^2 - 3x - 648 = 0$

This is a quadratic equation, i.e. an equation like $ax^2+bx+c=0$ . These equation can be solved - assuming they have a solution - with the following formula

$x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

If you plug the values from your equation, you have

$x_{1,2} = \dfrac{3\pm\sqrt{9-4\cdot(-648)}}{2} = \dfrac{3\pm\sqrt{9+2592}}{2} = \dfrac{3\pm\sqrt{2601}}{2} = \dfrac{3\pm51}{2}$

So, the two solutions would be

$x = \dfrac{3+51}{2} = \dfrac{54}{2} = 27$

$x = \dfrac{3-51}{2} = \dfrac{-48}{2} = -24$

But we know that x is positive, so we only accept the solution $x = 27$

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3 years ago

Calculate p² +3q when p=2 and q=2

QveST [7]

Answer:

Step-by-step explanation:

p² +3q

= 2² +3*2

=4 + 6

=10

4 0

3 years ago

Read 2 more answers

-2/3*3/5+5/2-3/5*1/6​

-2/33/5+5/2-3/51/6