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Katyanochek1 [597]
3 years ago
15

A cyclist planned to ride 9 1/2 miles but only managed to travel 3 7/8 miles. What fraction of his planned trip did he travel?

Mathematics
2 answers:
Goshia [24]3 years ago
7 0

Answer:

The cyclist traveled 31/76 of his planned trip.

Vanyuwa [196]3 years ago
3 0

Answer:

\frac{31}{76}

Step-by-step explanation:

We know that a cyclist wanted to ride 9\frac{1}{2} miles but only managed to travel 3\frac{7}{8} and we want to know what fraction he actually travelled so we have to divide the two fractions so

3\frac{7}{8} ÷ 9\frac{1}{2}

→ First convert to improper fractions

\frac{31}{8} ÷ \frac{19}{2}

→ Because it's dividing fractions we have to remember the rule of flipping the second fraction so then it becomes a multiplication

\frac{31}{8} × \frac{2}{19}

→ Simplify

\frac{31}{76}

So the cyclist had travelled only \frac{31}{76} of his planned trip

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There are several ways to solve a system of equation; one of these ways is the use of matrix.

<em>Jerry made a mistake at step 2</em>

From the attachment, the step 1 is represented as:

\mathbf{\frac 12R_1 \left[\begin{array}{cccc}1&1&1&0\\5&3&-2&-4\\3&2&1&1\end{array}\right] }

The equation in step 2 is given as:

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This means that:

We subtract the elements of row 2 from the elements of row 1, multiplied by 5

So, we have:

\mathbf{R_2 = 5\left[\begin{array}{cccc}1&1&1&0\end{array}\right] } - \left[\begin{array}{cccc}5&3&-2&-4\end{array}\right] }

Expand

\mathbf{R_2 = \left[\begin{array}{cccc}5&5&5&0\end{array}\right] } - \left[\begin{array}{cccc}5&3&-2&-4\end{array}\right] }

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\mathbf{R_2 = \left[\begin{array}{cccc}0&2&7&4\end{array}\right] }

So, the new row 2 elements should be:

\mathbf{ \left[\begin{array}{cccc}0&2&7&4\end{array}\right] }

However, the row 2 elements of Jerry's steps are:

\mathbf{R_2 = \left[\begin{array}{cccc}0&-2&-7&-4\end{array}\right] }

This means that:

Jerry made a mistake; and the mistake is at step 2

Read more about matrix at:

brainly.com/question/21848291

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