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Natasha_Volkova [10]
2 years ago
11

On the same graph draw line 2y-x=10 and y=3x​

Mathematics
1 answer:
Luba_88 [7]2 years ago
7 0

Answer:

Step-by-step explanation:

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nancy spent 7/8 hour working out at the gym she spent 5/7 of that time lifting weights what fraction of an hour did sje spentld
Juli2301 [7.4K]

\frac{9}{56}\\ Fraction of hour was spent by NAncy in lifting weights

Step-by-step explanation:

Time spent at the gym by Nancy = \frac{7}{8}\,hour

Time spent at lifting weights =  \frac{5}{7}\,hour

What fraction of hour she spent in lifting weights?

Solving:

Fraction of hour she spent in lifting weights= Time spend at the gym-Time spent at lifting weights

Fraction of hour she spent in lifting weights=\frac{7}{8}\,hour-\frac{5}{7}\,hour

=\frac{49}{56}-\frac{40}{56}\\=\frac{49-40}{56}\\=\frac{9}{56}\\

So, \frac{9}{56}\\ Fraction of hour was spent by Nancy in lifting weights

Keywords: Word Problems involving Fractions

Learn more about Word Problems involving Fractions at:

  • brainly.com/question/1648978
  • brainly.com/question/1677114
  • brainly.com/question/605571

#learnwithBrainly

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3 years ago
Plisss to na dzisiaj
CaHeK987 [17]
I’m sorry i don’t know the answer but i need to ask another question but i gave up answer a question first sorry
6 0
3 years ago
What is y=x+2. I need help fast please help
Mademuasel [1]

Answer:

Step-by-step explanation:

Its is a linear equation .that is to day a simple equation of a line whose values can be obtained through their intercept.intercept on x axis, y is zero and vice versa

7 0
3 years ago
You play a game that involves spinning a wheel. Each section of the wheel shown has the same area. Use a sample space to determi
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Answer:

is it fighet spinner or I am wrong hahahaa fighet spinner

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3 years ago
Read 2 more answers
On the 1st January 2014 Carol invested some money in a bank account.
Ghella [55]

Answer:

\large \boxed{\text{\pounds 23 360.00}}

Step-by-step explanation:

The formula for the accrued amount from compound interest is

A = P \left(1 + \dfrac{r}{n}\right)^{nt}

1. Amount in account on 1 Jan 2015

(a) Data:

a = £23 517.60

r = 2.5 %

n = 1

t = 1 yr

(b) Calculations:  

r = 0.025

\begin{array}{rcl}23517.60 & = & P\left (1 + \dfrac{r}{n}\right)^{nt}\\\\& = & P\left (1 + \dfrac{0.025}{1}\right)^{1\times1}\\\\& = & P (1 + 0.025)\\ & = & 1.025 P\\P & = & \dfrac{23517.60 }{1.025} \\\\& = & 22 944.00 \\\end{array}

The amount that gathered interest was £22 944.00 but, before the interest started accruing, Carol had withdrawn £1000 from the account.

She must have had £23 944 in her account on 1 Jan 2015.

(2) Amount originally invested

(a) Data

A = £23 944.00

\begin{array}{rcl}23 944.00 & = & 1.025 P\\P & = & \dfrac{23 944.00 }{1.025} \\\\& = & \mathbf{23 360.00} \\\end{array}\\\text{Carol originally invested $\large \boxed{\textbf{\pounds23 360.00}}$ in her account.}

3. Summary

1 Jan 2014      P = £23 360.00

1 Jan 2015     A =    23 944.00

     Withdrawal = <u>    -1  000.00 </u>

                     P =     22 944.00

1 Jan 2016    A =    £23 517.60

5 0
3 years ago
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