These are the 3 findings during the assessment of a child with epiglottitis: 1) child is drooling 2) child is agitated 3) child is not coughing/no coughing observed.
Nursing interventions would be: 1) Clear airway - use tongue depressor to avoid blocking of the airway due to excessive saliva production 2) Do not leave the child alone especially when he/she is agitated or restless 3) Let the child sit in a comfortable position, preferably in an upright position.
By organizing data<span>, a scientist can more easily interpret what has been observed. Making sense of </span>data<span> is called interpretation. Since most of the </span>data<span> scientist collect is quantitative, </span>data tables<span> and charts are usually used to organize the information. Graphs are created from </span>data tables<span>.
dont take it word for word
hope this helps</span>
<h2>Answer is option "C"</h2>
Explanation:
- NAD+ is a significant co-compound for hydride move catalysts fundamental to numerous metabolic procedures including glycolysis, pyruvate dehydrogenase complex, the TCA cycle and oxidative phosphorylation. The catalysts utilizing NAD+ in hydride-move are known as dehydrogenases or oxidoreductases, which catalyze the decrease of NAD+ into NADH
- NADH shaped from glycolysis (by means of the malate-aspartate transport) or the TCA cycle can respond at Complex I, otherwise called the NADH/coenzyme Q reductase in the mitochondrial electron transport chain [28]. Each NADH devoured by the mitochondria brings about the net creation of 3 ATP atoms (Figure 1). The total oxidation of one glucose atom creates 2 NADH reciprocals in cytosol and 8 NADH particles in mitochondria, empowering creation of 30 ATP counterparts from NADH of the aggregate of 36 ATP counterparts got from the entire procedure of catabolizing glucose to CO2 and H2O.
- Hence, the right answer is option C " the available NAD+ would be converted to NADH and glycolysis would stop due to lack of NAD+.
The correct answer is answer B
Answer:
So if the size of the pore is small then the rate of the diffusion will be very slow as the molecules will move from high concentration to low concentration in very slow rate.
Explanation:
I hope it helps you
