All categories

2 years ago

Please please help me

Mathematics

1 answer:

Archy [21]2 years ago

8 0

Answer:

The formula is: A = B * H where B is the base, H is the height, and * means multiply. The base and height of a parallelogram must be perpendicular. However, the lateral sides of a parallelogram are not perpendicular to the base.

Step-by-step explanation:

You might be interested in

At 2 PM, a thermometer reading 80°F is taken outside where the air temperature is 20°F. At 2:03 PM, the temperature reading yiel

Alexeev081 [22]

Use Law of Cooling:
$T(t) = (T_0 - T_A)e^{-kt} +T_A$
T0 = initial temperature, TA = ambient or final temperature

First solve for k using given info, T(3) = 42
$42 = (80-20)e^{-3k} +20 \\ \\ e^{-3k} = \frac{22}{60}=\frac{11}{30} \\ \\ k = -\frac{1}{3} ln (\frac{11}{30})$

Substituting k back into cooling equation gives:
$T(t) = 60(\frac{11}{30})^{t/3} + 20$

At some time "t", it is brought back inside at temperature "x".
We know that temperature goes back up to 71 at 2:10 so the time it is inside is 10-t, where t is time that it had been outside.
The new cooling equation for when its back inside is:
$T(t) = (x-80)(\frac{11}{30})^{t/3} + 80 \\ \\ 71 = (x-80)(\frac{11}{30})^{\frac{10-t}{3}} + 80$
Solve for x:
$x = -9(\frac{11}{30})^{\frac{t-10}{3}} + 80$
Sub back into original cooling equation, x = T(t)
$-9(\frac{11}{30})^{\frac{t-10}{3}} + 80 = 60 (\frac{11}{30})^{t/3} +20$
Solve for t:
$60 (\frac{11}{30})^{t/3} +9(\frac{11}{30})^{\frac{-10}{3}}(\frac{11}{30})^{t/3} = 60 \\ \\ (\frac{11}{30})^{t/3} = \frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}} \\ \\ \\ t = 3(\frac{ln(\frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}})}{ln (\frac{11}{30})}) \\ \\ \\ t = 4.959$

This means the exact time it was brought indoors was about 2.5 seconds before 2:05 PM

8 0

3 years ago

Kelvin finished $\frac{2}{3}$ 2 3 of his test in a $\frac{1}{2}$ 1 2 hour. Express this rate in hours per test.

svet-max [94.6K]

Complete Question

Kelvin finished 2/3 of his test in a 1/2 hour. Express this rate in hours per test.

Answer:

3/4 hours per test

Step-by-step explanation:

2/3 of his test = 1/2 hour

This rate in hours per test is calculated as:

x = 1/2 /2/3

x = 1/2 hour ÷ 2/3 test

x = 1/2 × 3/2

x = 3/4 hours per test

This rate in hours per test is given as 3/4 hours per test

4 0

2 years ago

A group of friends wants to go to the amusement park. They have $469.75 to spend on parking and admission. Parking is $10.75, an

attashe74 [19]

Answer:

Step-by-step explanation:

469.75-10.75 =

459 ÷ 38.25 =

8 0

2 years ago

Please help please need help ASAP

Anuta_ua [19.1K]

The altitude of a triangle is a line segment through a vertex and perpendicular to a line containing the side opposite the vertex.

Answer: $\overline{A F}$

6 0

2 years ago

I need help with the following if possible

scoundrel [369]

1. -1
2. 1
3. 5
4. -1
5.-1
6. -3

5 0

3 years ago

Read 2 more answers