Use Law of Cooling:

T0 = initial temperature, TA = ambient or final temperature
First solve for k using given info, T(3) = 42

Substituting k back into cooling equation gives:

At some time "t", it is brought back inside at temperature "x".
We know that temperature goes back up to 71 at 2:10 so the time it is inside is 10-t, where t is time that it had been outside.
The new cooling equation for when its back inside is:

Solve for x:

Sub back into original cooling equation, x = T(t)

Solve for t:

This means the exact time it was brought indoors was about 2.5 seconds before 2:05 PM
Complete Question
Kelvin finished 2/3 of his test in a 1/2 hour. Express this rate in hours per test.
Answer:
3/4 hours per test
Step-by-step explanation:
2/3 of his test = 1/2 hour
This rate in hours per test is calculated as:
x = 1/2 /2/3
x = 1/2 hour ÷ 2/3 test
x = 1/2 × 3/2
x = 3/4 hours per test
This rate in hours per test is given as 3/4 hours per test
Answer:
12
Step-by-step explanation:
469.75-10.75 =
459 ÷ 38.25 =
12
The altitude of a triangle is a line segment through a vertex and perpendicular to a line containing the side opposite the vertex.
Answer: 
1. -1
2. 1
3. 5
4. -1
5.-1
6. -3