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Answer:
The area of the deck after she doubles the length and width will be of 384 square feet.
Step-by-step explanation:
Area of a rectangle:
The area of a rectangle of length l and width w is given by:
Doubling length and width:
If we double the length and the width, the dimensions are 2l and 2w. Thus, the area will be of:
That is, if both dimensions are doubled, the area is multiplied by 4.
What will the area of the deck be after she doubles the length and width?
Was 96. Then, both dimensions were doubled, and the area has to be multiplied by 4.
96*4 = 384
The area of the deck after she doubles the length and width will be of 384 square feet.
Answer:
Perimeter of i - 22CM
Area of i - 13CM^2
Perimeter of ii -38CM
Area of ii -66CM^2
Perimeter of iii -30CM
Area of iii- 42CM^2
Perimeter of iv - 50CM
Area of iv- 126CM^2
Step-by-step explanation:
SHAPE I:
PERIMETER = S + S + S + S + S +S
= 7 + 1 + 5 +3 +4 +2
= 22CM
AREA = Part a - 4 * 2 = 8cm^2 part B - 5 *1 = 5cm^2
Total = 8 + 5 = 13cm^2
SHAPE II:
PERIMETER = S + S + S + S + S +S
= 4 + 4 +5 + 6 + 9 + 10
= 38 CM
AREA = Part a - 5 * 10 = 50 cm^2 part B - 4 *4 =16 cm^2
Total = 50+16 =66 cm^2
SHAPE III:
PERIMETER = S + S + S + S + S +S
= 9 + 2 + 3 + 4 + 6 + 6
= 30CM
AREA = Part a - 6 * 6 = 42cm^2 part B - 3 * 2= 6cm^2
Total = 36 + 6 =42 cm^2
SHAPE IV:
PERIMETER = S + S + S + S + S +S
= 9 + 10 + 4 + 6 + 6 + 15
= 50 CM
AREA = Part a -15 * 6 = 90 cm^2 part B - 9 *4 = 36cm^2
Total = 90 + 36 = 126cm^2
HOPE THIS HELPED
