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2 years ago

HAVE

Mathematics

1 answer:

Novosadov [1.4K]2 years ago

6 0

Answer:

Please could you repeat your question

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**Answer quick I will mark brainliest ***

Juliette [100K]

184/525

(this is me adding characters)

5 0

2 years ago

Evaluate the definite integral using the graph of f(x)<br> (Image included)

Tanya [424]

a) The first integral corresponds to the area under y = f(x) on the interval [0, 3], which is a right triangle with base 3 and height 5, hence the integral is

$\displaystyle \int_0^3 f(x) \, dx = \frac12 \times 3 \times 5 = \boxed{\frac{15}2}$

b) The integral is zero since the areas under the curve over [3, 4] and [4, 5] are equal but opposite in sign. In other words, on the interval [3, 5], f(x) is symmetric and odd about x = 4, so

$\displaystyle \int_3^5 f(x) \, dx = \int_3^4 f(x) \, dx + \int_4^5 f(x) \, dx = \int_3^4 f(x) \, dx - \int_3^4 f(x) \, dx = \boxed{0}$

c) The integral over [5, 9] is the negative of the area of a rectangle with length 9 - 5 = 4 and height 5, so

$\displaystyle \int_5^9 f(x) \, dx = -4\times5 = -20$

Then by linearity, we have

$\displaystyle \int_0^9 f(x) \, dx = \left\{\int_0^3 + \int_3^5 + \int_5^9\right\} f(x) \, dx = \frac{15}2 + 0 - 20 = \boxed{-\frac{25}2}$

8 0

2 years ago

The 10th term of an a.p is -27 and the 5th term is -12 .find the first term?

horsena [70]

Step-by-step explanation:

$a_{10} = - 27... (Given) \\\\\therefore a + 9d = - 27...... (1)\\\\a_{5} = - 12... (Given) \\\\\therefore a + 4d = - 12.......(2)\\\\$

Subtracting equation (2) from equation (1)

$a + 9d-( a + 4d )= - 27-(-12)\\\\\therefore a +9d - a-4d = - 27+12\\\\\therefore 5d = - 15\\\\\therefore d = \frac {- 15}{5}\\\\\huge \orange {\boxed {\therefore d = -3}} \\\\$

Substituting d = - 3 in equation (1), we find:

$a + 9\times (-3)= - 27\\\\\therefore a - 27 = - 27\\\\\therefore a = 27- 27\\\\\huge \red {\boxed {\therefore a = 0}}\\\\$

Hence, first term is zero.

3 0

3 years ago

How many zeros does the equation x^5 – 11^4+ 7 have?

ddd [48]

Answer:

Step-by-step explanation:

No. of Zeroes or Roots is equal to the degree of polynomial. Here, the degree of polynomial of the equation is 5. Hence, 5 Zeroes are possible.

5 0

2 years ago

Y=-4-x; domain = {-6, 2, 7}<br> Find range plz

UNO [17]

Step-by-step explanation:

domain is the valid interval for the x (input) values for the function.

the range is the valid interval for the y (result) values of the function.

so, we have a function definition and a valid domain interval for x. we therefore try the x values and see what result values they create. and that defines the range.

x = -6

y = 4 - -6 = 4 + 6 = +10

x = 2

y = 4 - 2 = +2

x = 7

y = 4 - 7 = -3

we have therefore a range of {-3, 2, 10}

3 0

2 years ago