Thanks
you were right
Answer:
1244 students
2064 students
hope it helped
Step-by-step explanation:
k(k+1)(k+2) - 3k(k+1)
k and (k+1) are common to both terms.
k(k+1)(k+2) - 3k(k+1) = k(k+1)[(k+2) - 3] = k(k+1)(k-1)
Answer: attached below
13
subtract 1 on both sides
then divide by 3
to get 13
