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4 years ago

What is the answer 2x +3(x-1)=7x+1-2(x+2

Mathematics

1 answer:

Serggg [28]4 years ago

3 0

Answer:

0=0 true for all x

Step-by-step explanation:

$2x+3\left(x-1\right)=7x+1-2\left(x+2\right)\\\\$

$2x+3x-3=7x+1-2\left(x+2\right)$

$5x-3=5x-3$

Hope this help ya

Red

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3 years ago

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3 years ago

Solve the system of equations. Show your work.<br> y = x^2 -3x +4 <br> x + y = 4

sesenic [268]

Answer:

x + y = 2 , y = x 2 − 4 x + 4

Replace all occurrences of

with x 2 − 4 x + 4

in each equation.

x 2 − 3 x + 4 = 2 y = x 2 − 4 x + 4

Solve for

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( 2 , 0 ) ( 1 , 1 )

The result can be shown in multiple forms.

Point Form:

( 2 , 0 ) , ( 1 , 1 )

Equation Form:

x=2 , y = 0 x = 1 , y = 1

Step-by-step explanation:

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3 years ago

charlene makes $10 per hour babysitting and $5 per hour gardening. She wants to make at least $80 a week, but can work no more t

swat32

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3 years ago

There are 10 cranberry and 15 strawberry juices. You randomly pick two juices. What's the probability you'll get two strawberry

lorasvet [3.4K]

Answer:

7/20

Explanation:

The theoretical probability, P (A), of an event, A, is:

P(A) = number of outcomes of event A / total number of possible outcomes

For 10 cranberry and 15 strawberry juices, the number of outcomes for two strawberry juices are:

Combination of 15 strawberry juices chosen in two:

$C^{15}_{2}=\frac{15!}{(15-2)!(2!)}=\frac{15!}{13!2!}=\frac{15\times 14}{2}=105$

The total number of possible outcomes is:

Combination of 25 juices chosen in two:

$C^{25}_{2}=\frac{25!}{(25-2)!(2!)}=\frac{25!}{23!2!}=\frac{25\times 24}{2}=300$

Thus, the probability of randomly picking two strawberry juices is:

P (two strawberry juices) = 105/300 = 7/20

Note that you can obtain it as the product of the probabilities that the first juice is a strawberry juice and the second juice is also strawberry juice:

$15/25\times 14/24=(15\times 25)/(14\times 24)=210/600=7/20$

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3 years ago