Answer:
The probability that a jar contains more than 466 g is 0.119.
Step-by-step explanation:
We are given that a jar of peanut butter contains a mean of 454 g with a standard deviation of 10.2 g.
Let X = <u><em>Amount of peanut butter in a jar</em></u>
The z-score probability distribution for the normal distribution is given by;
Z = ~ N(0,1)
where, = population mean = 454 g
= standard deviation = 10.2 g
So, X ~ Normal()
Now, the probability that a jar contains more than 466 g is given by = P(X > 466 g)
P(X > 466 g) = P( > ) = P(Z > 1.18) = 1 - P(Z 1.18)
= 1 - 0.881 = <u>0.119</u>
The above probability is calculated by looking at the value of x = 1.18 in the z table which has an area of 0.881.
These cannot be solved.- 3 unknowns require 3 equations
Amount left = $450 - $171 = $279
Amount left in Percentage = 279/450 x 100 = 62%
Answer: (C) 62%
Answer:
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