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BARSIC [14]
3 years ago
14

What is the width of a rectangle with a length of 12cm and area of 192cm2

Mathematics
2 answers:
vagabundo [1.1K]3 years ago
8 0
Area = Length x Width 

Given that length = 192cm² and the length = 12 cm, we plug these values into the equation and solve for the width:

192 = 12 x width

192 = 12width
 
width = 192 ÷ 12

width = 16 cm

Answer: Width = 16 cm
EastWind [94]3 years ago
7 0
Hello!

\rm Answer:

The width of the rectangle is \boxed{16} cm^2.

_____________________________

\rm Explanation:

Formula for area is:

A = l × w

We know that we must multiply the length by the width to find the area.

Since we want to find one of the rectangle's dimensions, and not the area, we'll use the opposite operation.

What's the opposite of multiplication? Division!

-------------------------------------------------------

Divide the area of the rectangle by its length to find the width:

W = A ÷ l

W = 192 ÷ 12

W = 16
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Luis purchased 24 purple plants and 8 pink plants. He wants to plant them in equal groups in hos garden. What is the largest num
luda_lava [24]

Answer:

8 groups.

Step-by-step explanation:

We are told that Luis purchased 24 purple plants and 8 pink plants. He wants to plant them in equal groups in his garden. We are asked to find out largest number of groups he can make.

To solve this problem we will find GCF of 24 and 8.

Factors of 24 are: 1,2,3,4,6,8,12 and 24.

Factors of 8 are 1,2,4 and 8.

We can see that greatest common factor of 24 and 8 is 8.

Therefore, Luis can make 8 groups each having 3 purple plants and 1 pink plant.  

6 0
3 years ago
An arithmetic sequence is represented in the following table. Enter the missing term of the sequence.
bija089 [108]

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4 0
3 years ago
Find the distance from the point (1, 4) to the line y = 1/3x – 3.
Otrada [13]

Answer: Distance between line and point =

4√5 -3/2√10

Step-by-step explanation:

Distance between the line is

= √ ((9-0)²+(0+1)²)

= √ (89+1)

= √90

= 3√10

Half of the line = 3/2√10

Distance of one side of the line and the point.

= √((9-1)²+(0-4)²)

= √((8)²+(-4)²)

=√64+16

= √80

= 4√5

Distance between line and point =

4√5 -3/2√10

8 0
2 years ago
Nolan correctly spelled 13/16 of his spelling words how is 13/16 written as a decimal
ivolga24 [154]

Answer:

0.8125

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
In the derivation of Newton’s method, to determine the formula for xi+1, the function f(x) is approximated using a first-order T
dimaraw [331]

Answer:

Part A.

Let f(x) = 0;

suppose x= a+h

such that f(x) =f(a+h) = 0

By second order Taylor approximation, we get

f(a) + hf'±(a) + \frac{h^{2} }{2!}f''(a) = 0

h = \frac{-f'(a) }{f''(a)} ± \frac{\sqrt[]{(f'(a))^{2}-2f(a)f''(a) } }{f''(a)}

So, we get the succeeding equation for Newton's method as

x_{i+1} = x_{i} + \frac{1}{f''x_{i}}  [-f'(x_{i}) ± \sqrt{f(x_{i})^{2}-2fx_{i}f''x_{i} } ]

Part B.

It is evident that Newton's method fails in two cases, as:

1.  if f''(x) = 0

2. if f'(x)² is less than 2f(x)f''(x)    

Part C.

In case  x_{i+1} is close to x_{i}, the choice that shouldbe made instead of ± in part A is:

f'(x) = \sqrt{f'(x)^{2} - 2f(x)f''(x)}  ⇔ x_{i+1} = x_{i}

Part D.

As given x_{i+1} = x_{i} = h

or                 h = x_{i+1} - x_{i}

We get,

f(a) + hf'(a) +(h²/2)f''(a) = 0

or h² = -hf(a)/f'(a)

Also,             (x_{i+1}-x_{i})² = -(x_{i+1}-x_{i})(f(x_{i})/f'(x_{i}))

So,                f(a) + hf'(a) - (f''(a)/2)(hf(a)/f'(a)) = 0

It becomes   h = -f(a)/f'(a) + (h/2)[f''(a)f(a)/(f(a))²]

Also,             x_{i+1} = x_{i} -f(x_{i})/f'(x_{i}) + [(x_{i+1} - x_{i})f''(x_{i})f(x_{i})]/[2(f'(x_{i}))²]

6 0
3 years ago
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