A laboratory technician needs to make a 63-liter batch of a 20% acid solution How can the laboratory technician combine a batch of an acid solution that is pure acid with another that is 10% to get the desired concentration?
2 answers:
Let x be the volume (liters) of pure (at 100%) acid needed Let y be the volume (liters) of the other acid (at 10%) needed The final solution will be: a) x+ y = 63 liters, AND their respective concentration in acid: is 100% x & 10% :y that will generate 63 liters at 20% b) x +0.1 y = 63x 0.2 = 12.6 Let's solve this system of 2 equations: x + y =63 x + 0.1 y = 12.6 Solving it will give you: x= 7 liters at 100% y = 56 liters at 10%
(63-x)= amount of 10% solution wanted
0.10(63-x) + x =0.20(63) =
6.3-0.1x+x=12.6
0.9x=6.3
X=7
63-7 = 56 liters
Check:
0.10(56) +7 = 0.2(63)
12.6 = 12.6
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