Ask question

Ask question

All categories

3 years ago

5

the flower shop has 40 times as many flowers in one cooler as Julia has in her bouquet. The cooler has 120 flowers. How many flo

wers in Julia ' s bouquet?

2 answers:

Simora [160]3 years ago

6 0

Just multiply 40 and 120 its 4,800

s344n2d4d5 [400]3 years ago

3 0

The answer is 4,800 . You have to multiply 120 and 40.

You might be interested in

Please help me and explain, thanks

ohaa [14]

Answer:

c

Step-by-step explanation:

Look at (3,1) (5,9) (4,5)

7 0

3 years ago

Need help whats<br>y=1/4x+2?

fgiga [73]

What do you mean? What are you trying to figure out?

3 0

3 years ago

Read 2 more answers

Definition of probability distribution

Doss [256]

Answer: probability distribution is a function of a discrete variable whose integral over any interval is the probability that the random variable specified by it will lie within that interval.

7 0

3 years ago

A sample of carbon has a mass of 0.000000000000000000034 kg. Express this mass in scientific notation.

BigorU [14]

Answer:

I don't know sorry

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Last June only 0.17 inches of rain fell all month. What is the difference between the average rainfall and the actual rainfall f

spin [16.1K]

Answer:

Part 1) 0.50 inches

Part 2) 1.14 inches

Part 3)

a) 1.25 inches

b) -0.32 inches

Step-by-step explanation:

The complete question in the attached figure

Part 1) Last June only 0.17 inches of rain fell all month. What is the difference between the average rainfall and the actual rainfall for the last June

Let

x ----> the average rainfall for the last June

y ----> the actual rainfall for the last June

The difference between the average rainfall and the actual rainfall for the last June is given by the expression

$(x-y)$

we have

$x=0.67\ in\\y=0.17\ in$

substitute

$0.67-0.17=0.50\ in$

Part 2) The departure from the average rainfall last July was -0.36 inches. How much rain fell last July?

we know that

The departure from the average is the difference between the actual amount of rain and the average amount of rain for a given month

Let

D -----> the departure from the average

x ----> the average rainfall for the last June

y ----> the actual rainfall for the last June

so

$D=y-x$

we have

$D=-0.36\ in\\x=1.5\ in$

substitute the given values

$-0.36=y-1.5$

solve for y

$y=1.5-0.36\\y=1.14\ in$

Part 3)

<u>Part a)</u> How much rain would have to fall in August so that the total amount of rain equals the average rainfall for these three months?

<u>Part b</u>) What would the departure from the average be in August in that

situation?

Part a) How much rain would have to fall in August so that the total amount of rain equals the average rainfall for these three months?

Find the average rainfall for these three months

Adds the average rainfall and divide by 3

$(0.67+1.5+1.57)/3=1.25\ in$

Part b) What would the departure from the average be in August in that

situation?

we know that

The departure from the average is the difference between the actual amount of rain and the average amount of rain for a given month

Let

D -----> the departure from the average

x ----> the average rainfall for the last June

y ----> the actual rainfall for the last June

so

$D=y-x$

we have

$x=1.57\ in\\y=1.25\ in$

substitute the given values

$D=1.25-1.57=-0.32\ in$

7 0

3 years ago