Answer:
yes it is correct
Step-by-step explanation:
Answer:
2/3
Step-by-step explanation:
1. add all the beads up together:
20+10+30= 60
2. add the blue and yellow beads up:
10+30= 40
3. put 40 over 60
40/60 which equals 2/3
4. the final answer:
2/3
First club
y= 40 + 10x y= 40 + 10(8) =120
Second club
y= 15x y= 15(8) =120
now plug a number of the answer choices in each equation until you get the same result for both
The answer is C
Answer:
80
Step-by-step explanation:
<u><em>A = Area of First Rectangle </em></u>
<u><em>B = Area of Second Rectangle </em></u>
<u><em>w = Width</em></u>
<u></u>
12(w)=320+B (1st Equation)
8(w) = B (2nd Equation)
w=B/8 <em><u>(Plug this value of w into the first equation)</u></em>
12B/8 = 320 +B <u><em>(you get this)</em></u>
12B= 2560 + 8B <u><em>(Simplify)</em></u>
4B = 2560
B =640 <em><u>plug this value into the 2nd equation</u></em>
8(w) = 640
w = 80
<em>To Test This</em>
12x80 = 960
8x80 = 640
<h3>960 - 640 = 320
<u><em>Therefore the answer is correct the width is 80</em></u></h3>
<h3 />
Answer:
A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error of the interval is given by:

In this problem, we have that:

99.5% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.07?
This is n when M = 0.07. So







A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07