Answer:
-46, 8, 28
Step-by-step explanation:
Answer:
D) (5,0)
Step-by-step explanation:
-5x + 4 ≤ y
-25 + 5 ≤ 0
-20 ≤ 0
y ≤ 2x + 2
0 ≤ 2(5) + 2
0 ≤ 27
Answer:
x= -5
Hope this helps!
Answer:
12 is the answer thanks for asking in
1.) The interval of the value of x is from -5 to 1, inclusive. Remember that what is asked is the absolute value, thus the sign does not matter even if you have to subtract x from 5. Thus, the maximum value would be obtained if the x is smaller, which is 1. The minimum value is obtained when x=-5.
Absolute maximum value:
x = - 5f(-5) = ║5 - 7(-5)^2║ = ║-170║=
170Absolute minimum value:
x = 1f(1) = ║5 - 7(1)^2║ = ║-2║=
2
2.) The Mean Value Theorem (MVT) applies to functions that are continuous and differentiable on the closed and open interval of a to b, respectively. Since the function is a quadratic function, MVT can be applied. Then, this means that there is a value of c which is between a and b. This could be determined using this formula according to MVT:
The differentiated form would be f'(x) = -2x. Then,
Thus, x = -1, x = -1/2, and x=0 all lie in the function 4-x^2.