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Margaret [11]
3 years ago
8

What are the coordinates of the turning point for the function f(x) = (x − 2)^3 + 1?

Mathematics
2 answers:
zhenek [66]3 years ago
5 0
The turning point is (2,1).

Hope this helps!
Ann [662]3 years ago
3 0

Answer:

(2,1)

Step-by-step explanation:

The given function is,

f(x) = (x -2)^3 + 1

Turning point of a graph is the point where the graph where the graph changes from increasing to decreasing (rising to falling) or decreasing to increasing (falling to rising).

For a cubic function, the critical point also serves as a turning point.

\Rightarrow f(x) = (x -2)^3 + 1

\Rightarrow f'(x) = 3(x -2)^2

For critical point,

\Rightarrow f'(x)=0

\Rightarrow 3(x -2)^2=0

\Rightarrow (x -2)^2=0

\Rightarrow x -2=0

\Rightarrow x=2

Then, f(2) = (2 -2)^3 + 1=1

So the critical point or turning point is (2,1)

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Find the quotient (line over 42 is repeating)
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 The correct answer is:  [C]:  " \frac{21}{11} " . 
_____________________________________________________

<span>Explanation:
_____________________________________________________
</span>
Let us begin by converting the:  
"0.42 (with the "repeating bar on the digits, "42") " ;  

into a fraction, as follows:
______________________________________________________
   Let  x = 0.42424242424242424242424242424242....

100x = 42.42424242424242424242424242424242....
______________________________________________________
    
         100x = 42.42424242424242424242424242424242....
    –         x =   0.42424242424242424242424242424242...
______________________________________________________
          99x = 42.000000000000000000000000000000.... ;

         →   99x = 42 ;  

Divide each side of the equation by " 99 " ;  
       to isolate "x" on one side of the equation; & to solve for "x" ; 
______________________________________________________
         →  99x / 99 = 42/99 = (42 ÷ 3) / (99 ÷ 3) = 14/ 33; 

         →  x = "\frac{14}{33}" .

So;  "0.42 (with a repeating bar over the digits, "42" ;

           is equal to:  "\frac{14}{33}" 
________________________________________________
 So, rewrite the question/problem being asked:
________________________________________________
  "Find the quotient:  
________________________________________________
   \frac{14}{33}  ÷ \frac{2}{9}  ;

=  \frac{14}{33} * \frac{9}{2}  ;

Note:  The "14" cancels to a "7" <span>; and</span> the "2" cancels to a "1" ; 
       →  {since:  " 14 ÷ 2 = 7 " ; and since:  " 2 ÷ 2 = 1 "} ;

Note : The "33" cancels to an "11" ; and the "9" cancels to a "3" ;
        →  {since:  " 33 ÷ 3 = 11 " ; and since:  " 9 ÷ 3 = 3 "} ;

And we can rewrite the problem as:
____________________________________________________
 
 " \frac{7}{11}  * \frac{3}{1} "  ;

  =  \frac{(7*3)}{(11*1}   =  \frac{21}{11} ; 

            → which is:  Answer choice:  [C]:  " \frac{21}{11} " .
____________________________________________________
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