A behsnsnnfnfnfhdbdbdnd hdjdns. Dhjdns fjjd rush d end d s
Answer:
![3m\sqrt[5]{2m^4p^4}](https://tex.z-dn.net/?f=3m%5Csqrt%5B5%5D%7B2m%5E4p%5E4%7D)
Step-by-step explanation:
We want to find the fifth root of 
. In order to do so, we need to factorise
Let's factorise 486 first:
486 = 2 * 243 = 2 * 
Ah, we see that can be taken out and becomes 3 outside of the 5th root since the 5th root of
Now look at the variables. We see that since we have p^"4", whose exponent is less than 5, it's impossible for us to write it as a power of 5, so we leave this in the root.
We also have m^"9", which can be written as m^"5" * m^"4". Again, we see that the m^"4" term will have to remain inside the root, but we can take out the m^"5", which becomes m.
Our final answer is thus: .
<em>~ an aesthetics lover</em>
If you multiply 11 by 15 which is 165 you will get your answer 165$
You can approximate e by substituting large values for (1 + 1/n)^n into the expression.
<h3>How to illustrate the expression?</h3>
It should be noted that an expression can simply be used to illustrate the information given in a data.
In this case, you can approximate e by substituting large values for (1 + 1/n)^n into the expression.
Learn more about expressions on:
brainly.com/question/723406
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Answer:
Step-by-step explanation:
C11 = (1×1) + (-1×3) = 1-3 = -2
C12 = (1×2) + (-1×4) = 2-4 = -2
C21 = (2×1) + (1×3) = 2+3 = 5
C22 = (2×2) + (1×4) = 4+4 = 8
