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Elden [556K]
3 years ago
14

What are the factors of x2 − 64? Prime (x − 4)(x + 16) (x − 8)(x − 8) (x + 8)(x − 8)

Mathematics
1 answer:
dem82 [27]3 years ago
4 0

{x}^{2}  -  {8}^{2}

(x - 8)(x  + 8)

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Option A: (x+3)^2+(y+2)^2=4 is the equation of the circle

Explanation:

The equation of the circle is x^{2} +y^2+6x+4y+10=1

We need to write the equation of the circle in standard form.

Let us subtract 10 from both sides of the equation.

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Simplifying, we get,

(x^{2} +6x+9)+(y^2+4y)=-9+9

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Similarly, we shall complete the square for the term \left(y^{2}+4 y\right) in the form of (a+b)^2

Thus, we have,

(x+3)^2+(y^2+4y+4-4)=0

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(x+3)^2+(y^2+4y+4)=4

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