3 years ago

QULLUNDU

1 answer:

7 0

I was over. I like it

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SashulF [63]

Given function:

$f(x)=xe^x$

The minimum value of the function can be found by setting the first derivative of the function to zero.

$f^{\prime}(x)=xe^x+e^x$ $\begin{gathered} xe^x+e^x\text{ = 0} \\ e^x(x\text{ + 1) = 0} \end{gathered}$

Solving for x:

$\begin{gathered} x\text{ + 1 = 0} \\ x\text{ = -1} \end{gathered}$ $\begin{gathered} e^x\text{ = 0} \\ \text{Does not exist} \end{gathered}$

Substituting the value of x into the original function:

$\begin{gathered} f(x=1)=-1\times e^{^{-1}}_{} \\ =\text{ -}0.368 \end{gathered}$

Hence, the minimum value in the given range is (-1, -0.368)

6 0

2 years ago

katrin2010 [14]

The answer is root!!

3 0

3 years ago

Nadya [2.5K]

There are only 2 perfect cubes in between 1000 and 2000.

11^3 = 1331
12^3 = 1728

8 0

3 years ago

olganol [36]

The answer is 6.00009

3 0

3 years ago

jeka57 [31]

Answer:

It is the last option

Step-by-step explanation:

7 0

3 years ago