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SashulF [63]
3 years ago
11

The sum of two consecutive numbers is n+1. What are the numbers?

Mathematics
1 answer:
dimaraw [331]3 years ago
5 0
Let, consecutive number is (n-1) & n
Then: n-1+n = n+1
2n-1 = n+1
2n-n = 1+1
n = 2
& (n-1) = 2-1 = 1

So, numbers are 1 & 2
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6 0
3 years ago
2x-1/4(12x+4)=3<br><br><br><br> 2x-1/4 (12x+4)=3
eduard
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3 0
3 years ago
Find the difference.
Vsevolod [243]

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9.\\7\dfrac{1}{6}-2\dfrac{5}{6}=6\dfrac{6+1}{6}-2\dfrac{5}{6}=6\dfrac{7}{6}-2\dfrac{5}{6}=(6-2)+\dfrac{7-5}{6}=4\dfrac{2}{6}=\boxed{4\dfrac{1}{3}}\\\\10.\\9\dfrac{3}{12}-4\dfrac{7}{12}=8\dfrac{12+3}{12}-4\dfrac{7}{12}=8\dfrac{15}{12}-4\dfrac{7}{12}=(8-4)+\dfrac{15-7}{12}=4\dfrac{8}{12}\\\\=4\dfrac{8:4}{12:4}=\boxed{4\dfrac{2}{3}}

5 0
3 years ago
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