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3 years ago

Find the sum or difference. (5a – 3b2 – a) + (b – 5 + 8a2)

Mathematics

1 answer:

natta225 [31]3 years ago

3 0

Answer:

The answer to your question is the third option

Step-by-step explanation:

Polynomial (5a - 3b² - a) + (b - 5 + 8a²)

1.- Group like terms

(8a²) + (5a - a) + (-3b²) + (b) + (-5)

2.- Simplify

8a² + 4a - 3b² + b - 5

3.- Order the polynomial

Result 8a² - 3b² + 4a + b - 5

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For an independent-measures anova comparing four treatment conditions, dfbetween = 3.

Tanya [424]

For an independent-measures anova comparing four treatment conditions, dfbetween = 3.

TRUE.

The dfbetween is given by the number of treatments minus 1.

3 0

3 years ago

Solve: 5x-4=6 please help meee

marta [7]

Answer:

x=2

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Joe needs to read 4 novels each month.

marusya05 [52]

9514 1404 393

Answer:

N = 4M
44

Step-by-step explanation:

If Joe reads 4 novels each month, the number of novels read will be 4 times the number of months that have passed.

N = 4M

When M=11, we have ...

N = 4×11 = 44

Joe needs to read 44 novels in 11 months.

4 0

3 years ago

The total length of wires a b and c is 445 cm wire a is 45 cm longer then wire b and wire b is half as long as wire c how long i

Oksana_A [137]

Answer:

$a = 145\ cm$

Step-by-step explanation:

Given

$a + b + c = 445$

$a = 45 + b$

$b = \frac{1}{2}c$

Required

Determine the length of a

Solve for c in $b = \frac{1}{2}c$

$2 * b = \frac{1}{2}c * 2$

$2b = c$

$c = 2b$

Substitute $c = 2b$ and $a = 45 + b$ in $a + b + c = 445$

$a + b + c = 445$

$45 + b + b + 2b = 445$

$45 + 4b = 445$

Solve for 4b

$4b = 445 - 45$

$4b = 400$

Solve for b

$b = 400/4$

$b = 100$

Recall that: $a = 45 + b$

$a=45+100$

$a = 145\ cm$

6 0

4 years ago

Find the set below using A=(5,6,9), and so on (Explanation is in picture)

anzhelika [568]

The result is: {5,6,9}

Step-by-step explanation:

Given

U = {0,1,2,......,10}

A = {5,6,9}

B = {0, 6, 7, 10}

We have to find

(A∩B)U(A∩B')

First of all,

B':

B' = U -B = {0,1,2,......,10} - {0, 6, 7, 10}

= {1,2,3,4,5,8,9}

A∩B':

A∩B' = {5,6,9} ∩ {1,2,3,4,5,8,9}

= {5,9}

A∩B:

A∩B = {5,6,9} ∩ {0, 6, 7, 10}

={6}

At the end we have to find union

(A∩B)U(A∩B') = {6} U {5,9}

(A∩B)U(A∩B') = {5,6,9}

Hence,

The result is: {5,6,9}

Keywords: Sets , Union

Learn more about sets at:

#LearnwithBrainly

8 0

3 years ago