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Orlov [11]
3 years ago
14

Find the sum or difference. (5a – 3b2 – a) + (b – 5 + 8a2)

Mathematics
1 answer:
natta225 [31]3 years ago
3 0

Answer:

The answer to your question is the third option

Step-by-step explanation:

Polynomial            (5a - 3b² - a) + (b - 5 + 8a²)

1.- Group like terms

                             (8a²) + (5a - a) + (-3b²) + (b) + (-5)

2.- Simplify

                             8a² + 4a - 3b² + b - 5

3.- Order the polynomial

Result                         8a² - 3b² + 4a + b - 5

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elect the correct answer. graph A graph B graph C graph D A credit card company uses these rules to calculate the minimum amount
laila [671]

The graph that correctly shows the minimum amount due for a credit amount (x)  is graph B.

<h3>How to determine the graph with the minimum amount due?</h3>

First of all, we would assign a variable to the different amount of money as follows:

  • Let x be the credit amount.
  • Let y be the minimum amount due.

Translating the word problem into an algebraic expression, we have;

For a bill of less than $100, the entire amount is due:

0 ≤ x < $100, therefore, y = x

For a bill of at least $100 but less than $500, the minimum due is $100: $100 ≤ x < $500, therefore, y = 100

For a bill of at least $500 but less than $1,000, the minimum due is $300:

$500 ≤ x < $1000, therefore, y = $300

For a bill of $1,000 or more, the minimum due is $500:

Since the credit limit is equal to $2000, we have $1000 ≤ x < $2000 and y = $500

In conclusion, the graph that correctly shows the minimum amount due for a credit amount (x)  is graph B.

Read more on graphs here: brainly.com/question/16883029

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5 0
1 year ago
Which number line shows the solution to 2/3x - 5 &gt; 3
NNADVOKAT [17]

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Step-by-step explanation:

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<h3>Given Equation:</h3>

\huge \purple {\rm { {x}^{2}  + kx - 12 = 0}}

<h3>Value:</h3>

\huge \purple {\rm {x = 4}}

<h3>To Find:</h3>

\huge \purple {\rm {The \: value \: of \: k.}}

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\huge \purple {\rm { {(4)}^{2}  + k(4) - 12 = 0}}

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\huge \purple {\rm {or, \: 4k =  - 4}}

\huge \purple {\rm {or, \: k =  \frac{ - 4}{4}  =  - 1}}

<h2>Answer:</h2>

\huge \purple {\sf {The \: value \: of \: k \: is \: -1}}

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