by the double angle identity for sine. Move everything to one side and factor out the cosine term.
Now the zero product property tells us that there are two cases where this is true,
In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of
, so
where
![n[/tex ]is any integer.\\Meanwhile,\\[tex]10\sin x-3=0\implies\sin x=\dfrac3{10}](https://tex.z-dn.net/?f=n%5B%2Ftex%20%5Dis%20any%20integer.%5C%5CMeanwhile%2C%5C%5C%5Btex%5D10%5Csin%20x-3%3D0%5Cimplies%5Csin%20x%3D%5Cdfrac3%7B10%7D)
which occurs twice in the interval
for
and
. More generally, if you think of
as a point on the unit circle, this occurs whenever
also completes a full revolution about the origin. This means for any integer
, the general solution in this case would be
and
.
The average score for the entire year is 88.44444, so by rounding down the answer is 88%
Answer:
69.81 sq. m. (rounded to 2 decimal places)
Step-by-step explanation:
The sector of a circle is "part" or "portion" of a circle. The formula for the area of a sector is:
Where
is the central angle
r is the radius
Given the figure, the arc is given as 80 degrees, but not the central angle of the shaded sector. But from geometry we know that the central angle and the intercepted arc have the same measure. So we can say:
Also, the radius of the circle shown is 10 meters, so
r = 10
Now, we substitute in formula and find our answer:
Thus,
The area of the shaded sector is 69.81 sq. meters.
Answer: Y = -y - 12
Step-by-step explanation:
