The string is assumed to be massless so the tension is the sting above the 12.0 N block has the same magnitude to the horizontal tension pulling to the right of the 20.0 N block. Thus,
1.22 a = 12.0 - T (eqn 1)
and for the 20.0 N block:
2.04 a = T - 20.0 x 0.325 (using µ(k) for the coefficient of friction)
2.04 a = T - 6.5 (eqn 2)
[eqn 1] + [eqn 2] → 3.26 a = 5.5
a = 1.69 m/s²
Subs a = 1.69 into [eqn 2] → 2.04 x 1.69 = T - 6.5
T = 9.95 N
Now want the resultant force acting on the 20.0 N block:
Resultant force acting on the 20.0 N block = 9.95 - 20.0 x 0.325 = 3.45 N
<span>Units have to be consistent ... so have to convert 75.0 cm to m: </span>
75.0 cm = 75.0 cm x [1 m / 100 cm] = 0.750 m
<span>work done on the 20.0 N block = 3.45 x 0.750 = 2.59 J</span>
Answer:
6,10,or 30 is your answer
No.
Double 5 and add 1 is 5(2)+1 = 11
Add 1 to 5 then double it: (1+5)2 = 12
Answer:
x=53/9
Step-by-step explanation:
(x-2):5=7:9
9x-18=35
9x=35+18
9x=53
x=53/9
Answer:
Step-by-step explanation:
The sine of an angle is defined as the ratio between the opposite side and the hypotenuse of a given right-angled triangle;
sin x = ( opposite / hypotenuse)
The opposite side to the angle x is thus 1 unit while the hypotenuse is 3 units. We need to determine the adjacent side to the angle x. We use the Pythagoras theorem since we are dealing with right-angled triangle;
The adjacent side would be;
The cosine of an angle is given as;
cos x = (adjacent side / hypotenuse)
Therefore, the cos x would be;
