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lys-0071 [83]
3 years ago
6

Help pleaseeeeeeeeeeeeeeeeeee

Mathematics
2 answers:
vladimir1956 [14]3 years ago
8 0

Answer:

Answer:5

Step-by-step explanation:

klemol [59]3 years ago
7 0

The first equation

6x^2 -18x-24=0

-the graph opens up

6(x^2 -3x -4)=0

6(x^2 -3x +9/4-4-9/4)=0

6(x-3/2)-25x6/4=

6(x-3/2)-75/2

-Vertex is at (3/2, -75/2)

-Axis of symmetry is x=3/2

Second equation

3r^2 -16r -12=0

-the graph opens up

...

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Anettt [7]

The resulting equation will represent a line whose slope is 1/2 times the slope of the line

<h3>How to determine the slope of the new line?</h3>

The equation of the line is given as:

y = 3x/a + 5

The constant a is a positive constant.

So, when the value of a in the equation is doubled, we have:

y = 3x/2a + 5

A linear equation is represented as

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So, we have:

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Substitute m1 = 3/a in m2 = 3/2a

m2 = 1/2 * m1

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2 years ago
If log_10(x) = 3 + log_10(y), then find x/y
Lina20 [59]

Answer:

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Step-by-step explanation:

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7 0
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