Answer:
I think PEMDAS would be helpful for this.
Step-by-step explanation:
Answer : The rate of depreciation is, $16000
Step-by-step explanation :
Formula used to calculate the rate of depreciation is:
Given:
Purchase price of asset = $15000
Salvage value = $7000
Estimate life asset = 3 years
Now put all the given values in the above formula, we get:
Deprecation rate = $16000
Therefore, the rate of depreciation is, $16000
Answer:
Step-by-step explanation:
N(106,14²)
(calculated using excel, let me know if you were supposed to use a normal table) = 0.4715
85.34
Q1:96.56
Q3:115.44
IQR (which is Q3-Q1)= 115.44-96.56= 18.88
Answer:
If you multiply the numbers you will get
0.030634
The complete question is
Find the volume of each sphere for the given radius. <span>Round to the nearest tenth
we know that
[volume of a sphere]=(4/3)*pi*r</span>³
case 1) r=40 mm
[volume of a sphere]=(4/3)*pi*40³------> 267946.66 mm³-----> 267946.7 mm³
case 2) r=22 in
[volume of a sphere]=(4/3)*pi*22³------> 44579.63 in³----> 44579.6 in³
case 3) r=7 cm
[volume of a sphere]=(4/3)*pi*7³------> 1436.03 cm³----> 1436 cm³
case 4) r=34 mm
[volume of a sphere]=(4/3)*pi*34³------> 164552.74 mm³----> 164552.7 mm³
case 5) r=48 mm
[volume of a sphere]=(4/3)*pi*48³------> 463011.83 mm³----> 463011.8 mm³
case 6) r=9 in
[volume of a sphere]=(4/3)*pi*9³------> 3052.08 in³----> 3052 in³
case 7) r=6.7 ft
[volume of a sphere]=(4/3)*pi*6.7³------> 1259.19 ft³-----> 1259.2 ft³
case 8) r=12 mm
[volume of a sphere]=(4/3)*pi*12³------>7234.56 mm³-----> 7234.6 mm³
