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3 years ago

7

Given the equation square root of quantity 3x plus 6 end quantity equals 3, solve for x and identify if it is an extraneous solu

tion.

1 answer:

MissTica3 years ago

4 0

Step-by-step explanation:

3x+6=3

-6 -6

3x =-3

÷3 ÷3

x= -1

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The sum of 6 and the product of 3 and d

Novosadov [1.4K]

Answer:

6 + 3d

Step-by-step explanation:

First, we can translate from English words to mathematical operations:

– Product: the result of multiplication

– Sum: the result of addition

So, we can rephrase the original sentence as “the result of adding 6 and (the result of multiplying 3 and d)”

When we multiply a constant like 3 by a variable like d, we usually write the two next to each other, which would be “3d” in this case. We can replace that last sentence in symbols with 6 + 3d

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At the north campus of a performing arts schools, 10% of the students are music majors. At the south campus, 70% of the students

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Step-by-step explanation:

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3 years ago

Put answer in coordinate form: 2x + 2y = -2 and 9x - 6y = 36

zhannawk [14.2K]

Coordinate form is (x,y) using the variables respectively.

2x+2y=-2
-2y
2x= -2-2y
/2

x=-1-y

9x-6y=36
9 (-1-y)-6y=36
-9-9y-6y=36
+9.
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3 years ago

A store has forty two diet sodas and six regular sodas. How many times more diet sodas did they have than regular sodas?

scoundrel [369]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

The sequence {an) is defined by ao = 1 and

otez555 [7]

<h3>Answer: 31</h3>

=======================================

Work Shown:

Use the value of a0 to find the value of a1. The idea is you double the previous value, and then add 1.

$a_{n+1} = 2*(a_n) + 1\\\\a_{0+1} = 2*(a_0) + 1\\\\a_{1} = 2*(1) + 1\\\\a_{1} = 3\\\\$

Which is then used to find the value of a2. Follow the same process as before (double the previous value and then add 1).

$a_{n+1} = 2*(a_n) + 1\\\\a_{1+1} = 2*(a_1) + 1\\\\a_{2} = 2*(3) + 1\\\\a_{2} = 7\\\\$

This is used to find a3

$a_{n+1} = 2*(a_n) + 1\\\\a_{2+1} = 2*(a_2) + 1\\\\a_{3} = 2*(7) + 1\\\\a_{3} = 15\\\\$

Finally we can now find a4

$a_{n+1} = 2*(a_n) + 1\\\\a_{3+1} = 2*(a_3) + 1\\\\a_{4} = 2*(15) + 1\\\\a_{4} = 31\\\\$

Recursive sequences like this aren't too bad if n is small, but as n gets larger, things become more tedious. For those cases, its best to try to find a closed form equation. If not, then the next best thing is using a spreadsheet to automate the process.

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3 years ago