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Sladkaya [172]
3 years ago
6

If x=25 when y=15, find x when y=24

Mathematics
1 answer:
mars1129 [50]3 years ago
7 0

Answer:

\frac{24 \times 25}{15}  = 40

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Area of a triangle with verticals of (-4,1),(-7,5),(0,1)
Lynna [10]

Answer:

8 ft^2

Step-by-step explanation:

I assume that the three points given are the vertices of the triangle. So the three points are:

A (-4,1)

B (-7,5)

C (0,1)

The area of a triangle is given by:

A=\frac{1}{2}bh

where b is the base and h is the height.

Here we can take as follows:

- We can take the base to be the side AC, so that its length is equal to the distance between the two points:

AC=\sqrt{(0-(-4))^2+(1-1)^2}=4

- The height of the triangle is therefore the perpendicular distance between AC and point B. This is equivalent the difference in the x-coordinate between any point on AC and B, so:

h=(5-1)=4 ft

Therefore, the area of the triangle is:

A=\frac{1}{2}(4)(4)=8 ft^2

7 0
3 years ago
(-1) power 50 is what
Tcecarenko [31]

(-1) to the power of an even number is +1.

(-1) to the power of an odd number is -1.

Since 50 is an even number, (-1)⁵⁰ = 1.

7 0
1 year ago
What is the degree measure of arc UTR
Paladinen [302]

Answer:

212°

Step-by-step explanation:

arc UTR = 180+32 = 212°

3 0
3 years ago
I need help :( the question is hard can you explain and show your work ty
Anika [276]
20%
step by step explanation
3 0
3 years ago
Read 2 more answers
Of the 9-letter passwords formed by rearranging the letters AAAABBCCC (4 A's, 2 B's, and 3 C's), I select one at random. Determi
Tanya [424]

Answer:

a) 3

b) (8!/9!)-(7!/9!)

c) (1-(8!/9!))*(7!/9!)

Step-by-step explanation:

a)With 4 As ;  2Bs and 3Cs it is possible to get a palindrome if you fixed the  letters C according to: (2) in the extremes of the word and the other one at the center therefore you only have palindrome in the following cases

<u>C</u> (       ) <u>C</u> (       ) <u>C</u>

To fill in the gaps we have  4 letters  A and 2 letters B, wich we have two divide in two palindrome gaps,  

AAB         and    BAA the palindrome is  C  AAB C BAA C

BAA         and    AAB    "           "           is  C  BAA C AAB C  

ABA         and    ABA    "           "           is  C  ABA C ABA C

b) 4 A  ;   2B  ; 3C

We have the total number of elements  9, so the total number of possible outcomes is : 9!

Total events: 9!

if we fixed 3 C we have (the group of 3 Cs becoming one element) so the total amount of events with 3 adjacent Cs is: 7!

Therefore the probability of having 3 adjacent Cs is: 7!/9!

If we fixed only 2 Cs we have:

4 A  ; 2 B  ; 2C  : 1C

Total number of words (events) in this case is 8! (2C becomes 1 element)

so the total numbers of events is 8! the probability in this case is 8!/9!(this value includes cases of adjacent 3 Cs previous calculated ) so this value minus the case of 3 adjacent Cs ) give us 2 adjacent C and the other no next to them

Probability (of words with 2 adjacent Cs and the other no next to them is); 8!/9! - 7!/9!

c) Probability of B apart from each other is the whole set of events minus those where 2 B are adjacent or (become 1 element)

4 A ; 2B ; 3C

Total of events 9! and events with adjacent B is 8!/9!

Therefore the probability of words with 3 adjacent Cs and 2 B separeted is

the probability of 3 adjacent Cs (7!/9!) times probability of words with no adjacent Bs wich is (1-(8!/9!))*(7!/9!)

5 0
3 years ago
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