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8090 [49]
3 years ago
9

Ajax is 5 and 1 fourth feet tall. His sister is 3 eighths foot shorter than Ajax How tall is Ajax Sister?

Mathematics
2 answers:
user100 [1]3 years ago
7 0

Answer:

4\frac{3}{4} feet tall

Step-by-step explanation:

Ajax is "5 and 1 fourth feet tall", which can be written as the mixed number 5\frac{1}{4} .

His sister is "3 eighths foot shorter", so she's 3/8 feet shorter than 5 1/4.

So, this is just a subtraction problem:

5\frac{1}{4} -\frac{3}{8}

To solve this, we want to convert 5 1/4 into an improper fraction, which is: \frac{21}{4} . Now, we want to find a common denominator. In this case, that common denominator is 8, so \frac{21}{4} =\frac{42}{8} .

Finally, we subtract 3/8 from 42/8: \frac{42}{8} -\frac{3}{8} =\frac{39}{8} . So, Ajax's sister is 39/8 feet. Converting this into a mixed number, we have: 39/8 = 4\frac{6}{8} =4\frac{3}{4} .

Therefore, Ajax's sister is 4\frac{3}{4} feet tall.

Hope this helps!

lord [1]3 years ago
5 0

Answer:

4⅞ ft

4 and 7 eighths feet

Step-by-step explanation:

5¼ - ⅜

5¼ = 21/4

21/4 - 3/8

[21×2 - 3]/8

(42 - 3)/8

39/8

4 ⅞

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Answer:

Received a compliment: wore a tie =25

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Did not receive a compliment: did not wear a tie =16

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Step-by-step explanation:

There were 11 days where she neither wore a tie nor received a compliment. This puts 11 in the bottom right box.

There were 30 days in total where she received a compliment. This means the first row (received a compliment ) adds to 30.

There were 16 days in total where she did not wear a tie. This means the second column adds to 16.

Now since there is 11 in the bottom-right box,  and the right column adds to 16, this puts 16-11 = 5 into the upper-right box.

And since the upper column (received a compliment) adds to 30, the upper right column is 5, this puts 30-5 =25 into the upper left box.

What we have now is 25 in the upper-left box, 5 in upper-right box, 11 in bottom-right box.; we are missing the bottom-left box.

Since the total number of days is 50, what goes in the bottom left box is 50 - (25+5+11) = 9.

Thus we have

Received a compliment: wore a tie =25

Received a compliment: did not wear a tie = 5

Did not receive a compliment: did not wear a tie =16

Did not receive a compliment: wore a tie = 9

8 0
3 years ago
Suppose A and B represent two different school populations where A > B and A and B must be greater than 0. Which of the follo
ryzh [129]

Answer:

The value for the expression (A+B)^{2} is the largest

Step-by-step explanation:

Since both A and B must be greater than 0 and A>B then we can assume the least possible values for B=1 and A=2.

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i) 2(A+B) = 2(2+1) = 2*3 = 6

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iii) A^{2} + B^{2}  = 2^{2} +1^{2} = 4+1 = 5

iv) A^{2} - B^{2} = 2^{2} - 1^{2} = 4-1 =3

Inspecting the answers of the above four expressions, we see that the value for the expression (A+B)^{2} is the largest.

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6 0
3 years ago
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What is the mean of 5 and 7
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Answer:

The mean is the number in the middle of the two. The mean of 5 and 7 is 6.

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