Answer: A sequence of similar transformations of dilation and translation could map △ABC onto △A'B'C'.
Step-by-step explanation:
Similar transformations: If one figure can be mapped onto the other figure using a dilation and a congruent rigid transformation or a rigid transformation followed by dilation then the two figures are said to be similar.
In the attachment △ABC mapped onto △A'B'C' by a sequence of dilation from origin and scalar factor k followed by translation.
The perimeter of the shape is 94 cm and the area is 462 sq cm.
Step-by-step explanation:
Given,
The radius (r) = 14 cm
To find the area and perimeter of the given shape.
The given shape is 
of the full circle.
Formula
The perimeter of the circle = 2πr
The perimeter of the given shape = (2πr)+r+r = (2πr)+2r
The area of the circle = πr²
Now,
The perimeter of the given shape = (2×
×14)+2×14 = 94 cm
The area of the given shape = (πr²)
= ××14² = 462 sq cm
Y=3x-4
This affects the previous line because now the slope is a positive which completely turns it around. and the Y intercept is now on the opposite side of the X axis
Answer:
2.4 x 10
Step-by-step explanation:
You move the decimal over from 24. to 2.4. BTW 1 IS THE EXPONENT
Answer:
25,31,37
Step-by-step explanation:
n should be positive integer number. The three numbers in both sequences have different term number n but same value. We can equalize each nth term in the question to "a" which represents one of the three numbers.
a=2n-1, then n=(a+1)/2
a=3n+1, then n=(a-1)/3
remember the two n above are different but both should be positive integer. That means, we have to find the "a" number that gives me an integer n for the first equation. The possible numbers between 20 to 40 are 22,25,28,31,34,37,40.
The possible numbers for the second equation are 21,23,25,27,29,31,33,35,37,39.
Now find the common numbers between the two sets above. They are 25,31,37
