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evablogger [386]
3 years ago
7

A box has 14 camera of which 6 are refurbished and 8 are new. If four of these 14 cameras are selected at random without replace

ment, what is the probability that (i) one new camera will be selected? (ii) at most one new camera will be selected?
Mathematics
1 answer:
lutik1710 [3]3 years ago
4 0

Answer:

160/1001, 175/1001

Step-by-step explanation:

i) There are:

₈C₁ ways to choose 1 new camera from 8 new cameras

₆C₃ ways to choose 3 refurbished cameras from 8 refurbished cameras

₁₄C₄ ways to choose 4 cameras from 14 cameras

The probability is:

P = ₈C₁ ₆C₃ / ₁₄C₄

P = 8×20 / 1001

P = 160 / 1001

P ≈ 0.160

ii) At most one new camera means either one new camera or no new cameras.  We already found the probability of one new camera.  The probability of no new cameras is the same as the probability of choosing 4 refurbished cameras:

P = ₆C₄ / ₁₄C₄

P = 15 / 1001

So the total probability is:

P = 160/1001 + 15/1001

P = 175/1001

P ≈ 0.175

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UNO [17]

Considering the perimeter concept, we have that:

  • Danielle's mistake is that she did not consider two outside edges, one of length 6x - 4 and the other of length 12x + 3.
  • The correct perimeter, in feet, is: P = 50x + 27.

<h3>What is the perimeter of a polygon?</h3>

The perimeter of a polygon is given by the sum of all the lengths of the outside edges of the polygon.

For this problem, the outside edges are given as follows:

  • 2 of 6x - 4, due to the isosceles triangle.
  • 2 of 12x + 3, due to the rectangle.
  • 1 of 14x + 13, also due to the rectangle, and only one, because of the other part of the rectangle with the same length is internal to the prism;

Danielle's mistake is that she did not consider two outside edges, one of length 6x - 4 and the other of length 12x + 3. Considering all the edges, the perimeter is given by:

P = 2(6x - 4) + 2(12x + 3) + 14x + 13

P = 12x - 8 + 24x + 6 + 14x + 13

P = 12x + 24x + 14x + 8 + 6 + 13

P = 50x + 27.

More can be learned about the perimeter of a polygon at brainly.com/question/3310006

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