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Inessa05 [86]
3 years ago
9

A store owner want to develop a new snack mix by mixing chocolate and trail mix. How many pounds of chocolate costing $16.50 per

pound should be mixed with 13 pound of trail mix costing $2.90 per pound to create a mixture worth $9.13. (round to the nearest pound)
Mathematics
1 answer:
irina [24]3 years ago
6 0

Answer:

11 pounds

Step-by-step explanation:

Let x pounds of chocolate costing $16.50 per pound mixed with 13 pound of trail mix costing $2.90 per pound to create a mixture worth $9.13,

Thus, the total quantity of trail mix = ( x + 13 ) pounds,

Also, the cost price of x pounds of chocolate + cost price of 13 pounds of trail mix = cost price of resultant trail mix

∵ total cost = number of pounds × price per pound

⇒ 16.50x + 2.90(13) = 9.13(x+13)

⇒ 16.50x + 37.7 = 9.13x + 118.69

⇒ 16.50x - 9.13x = 118.69 - 37.7

⇒ 7.37x = 80.99

⇒ x = 10.989145 ≈ 11

Hence, 11 pounds of chocolate should be mix.

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2 years ago
Is the point 3/5 and 4/5 corresponds to an angle in the unit circle what is the csc
Mariulka [41]

<u>Answer:</u>

csc = 5/4

<u>Step-by-step explanation:</u>

Assuming that the two given points 3/5 and 4/5 are the two sides of a triangle and a right angle 0  with legs x and y and z as its hypotenuse.

Then using Pythagoras Theorem:

z^2=x^2+y^2

z^2=(\frac{3}{5} )^2+(\frac{4}{5} )^2

z^2 = \frac{9}{25} + \frac{16}{25}

z^2=\frac{25}{25}

z^2=1

Taking square root on both the sides:

z=1

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and we know that csc = \frac{1}{sin\alpha }

Therefore, csc = 5/4.

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Determine the region of the xy-plane where the solution of the DE would have a unique solution passing through the point (x0,y0)
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(9-y^2)\dfrac{dy}{dx}= x^4\\(9-y^2)dy = x^4 dx\\\int (9-y^2)dy =\int x^4 dx\\9y -\dfrac{y^3}{3} = \dfrac{x^5}{5}+C

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9y -\dfrac{y^3}{3} = \dfrac{x^5}{5}+ 9y_0 -\dfrac{y_0^3}{3}-\dfrac{x_0^5}{5}

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