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Aneli [31]
3 years ago
9

Parallelogram JKLM is shown on the coordinate plane below:

Mathematics
1 answer:
timofeeve [1]3 years ago
6 0
A 270° counterclockwise rotation leads to this transformation:

(x,y) → (y, - x)

So, we have

original point        new point

J (-6,2)           →     J' (2,6)

K (-4,6)          →     K' (6,4)

L (-3,3)          →      L' (3,3)

M (-5,-1)        →      M' (-1,5)

So, you have the points J', K', L', and M' that define the new parallelogram.

Answer: The coordinates of the endpoints of the side congruent to side KL are the coordinates of K' and L' which are (6,4) and (3,3).



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7 0
3 years ago
PLEASE HELP!! URGENT!!!! UNIT TEST!!!!
slavikrds [6]

ANSWER

y=-\frac{4}{3}x+\frac{16}{3}


Or

3y+4x=16


EXPLANATION


Let us find the gradient of the line:

-3x+4y=4 by rewriting it in the slope intercept form.


\Rightarrow 4y=3x+4


We divide through by 4 now;


\Rightarrow y=\frac{3}{4}x+1


This is now in the form;

y=mx+c

where

m=\frac{3}{4} is he slope.


This implies that the slope of the line that is perpendicular to this line will be the negative reciprocal of m=\frac{3}{4} .


Thus the perpendicular line has slope,

m=\frac{-1}{\frac{3}{4}}= -\frac{4}{3}.


Let the perpendicular line have equation,


y=mx+c

When we substitute the slope we have;


y=-\frac{4}{3}x+c

We substitute the point. (4,0) to find c.


0=-\frac{4}{3}(4)+c


0=-\frac{16}{3}+c


\frac{16}{3}=c

We substitute c to obtain;


y=-\frac{4}{3}x+\frac{16}{3}


Or

3y+4x=16

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A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon
fiasKO [112]

Answer:

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon they'd received in the mail.

This means that n = 603, \pi = \frac{142}{603} = 0.2355

95% confidence level

So \alpha = 0.05, z is the value of Z that has a p-value of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 - 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2016

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 + 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2694

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

8 0
2 years ago
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