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3 years ago

Parallelogram JKLM is shown on the coordinate plane below:

1 answer:

6 0

A 270° counterclockwise rotation leads to this transformation:

(x,y) → (y, - x)

So, we have

original point        new point

J (-6,2)           →     J' (2,6)

K (-4,6)          →     K' (6,4)

L (-3,3)          →      L' (3,3)

M (-5,-1)        →      M' (-1,5)

So, you have the points J', K', L', and M' that define the new parallelogram.

Answer: The coordinates of the endpoints of the side congruent to side KL are the coordinates of K' and L' which are (6,4) and (3,3).

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How do I solve this inequality

Makovka662 [10]

3x+5x/4≤34
leat common multiple=4
12x+5x≤136
17x≤136
x≤136/17
x≤8

Answer: x≤8 or (-∞,8]

7 0

3 years ago

PLEASE HELP!! URGENT!!!! UNIT TEST!!!!

slavikrds [6]

ANSWER

$y=-\frac{4}{3}x+\frac{16}{3}$

$3y+4x=16$

EXPLANATION

Let us find the gradient of the line:

$-3x+4y=4$ by rewriting it in the slope intercept form.

$\Rightarrow 4y=3x+4$

We divide through by 4 now;

$\Rightarrow y=\frac{3}{4}x+1$

This is now in the form;

$y=mx+c$

where

$m=\frac{3}{4}$ is he slope.

This implies that the slope of the line that is perpendicular to this line will be the negative reciprocal of $m=\frac{3}{4}$ .

Thus the perpendicular line has slope,

$m=\frac{-1}{\frac{3}{4}}= -\frac{4}{3}$ .

Let the perpendicular line have equation,

$y=mx+c$

When we substitute the slope we have;

$y=-\frac{4}{3}x+c$

We substitute the point. $(4,0)$ to find c.

$0=-\frac{4}{3}(4)+c$

$0=-\frac{16}{3}+c$

$\frac{16}{3}=c$

We substitute c to obtain;

$y=-\frac{4}{3}x+\frac{16}{3}$

$3y+4x=16$

7 0

3 years ago

Read 2 more answers

Angles H and F are corresponding angles<br> True or False?

lutik1710 [3]

True! they are corresponding angles.

5 0

2 years ago

Read 2 more answers

Mhm help please! quarantine got me

Karolina [17]

The answer would be 9.4

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3 years ago

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A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon

fiasKO [112]

Answer:

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon they'd received in the mail.

This means that $n = 603, \pi = \frac{142}{603} = 0.2355$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a p-value of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 - 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2016$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 + 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2694$

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

8 0

2 years ago