The answer is C. 1 is considered the multiplicative identity because when you multiply it by a number, you get that same number as a product. similarly, 0 is considered the additive identity because adding 0 to anything returns the same number.
the distributive property would look more like 2(1+2) = 2(1) + 2(2)
associative property would be like 2*(3*4) = (2*3)*4
commutative would look like 2*1 = 1*2
Answer:
y =4
Step-by-step explanation:
8(y – 2) = 4y
Distribute
8y -16 =4y
Subtract 8y from each side
8y-8y -16 = 4y -8y
-16 = -4y
Divide each side by -4
-16/-4 = -4y/-4
4 = y
Step-by-step explanation:
#1.
(a + 2b)²
<em>Using identity (x + y)² = x² + 2xy + y², we get:</em>
= (a)² + (2b)² + 2 × (a) × (2b)
= a² + 4b² + 4ab
= a² + 4ab + 4b² Ans.
#2.
(5x - 3y)²
<em>Using identity (a - b)² = a² - 2ab + b², we get:</em>
= (5x)² + (3y)² - 2 × (5x) × (3y)
= 25x² + 9y² - 30xy
= 25x² - 30xy + 9y² Ans.
#3.
(3a + 4)(3a - 4)(9a² + 16)
<em>Using identity (x + y)(x - y) = x² - y², we get:</em>
= [(3a)² - (4)²][9a² + 16]
= (9a² - 16)(9a² + 16)
= (9a²)² - (16)²
= 81a⁴ - 256 Ans.
First you have to solve the multiplication:
102 + 6*7+8 = 102 + 42 + 8
At last you have to add all:
102 + 42 + 8 = 152
Answer:
is the resulting expression after grouping
Step-by-step explanation:
Given:
Now taking common 
from 1st 2 numbers and and 3 common from last we get
Now taking x-3 common from both numbers we get
which is the final equation after grouping
