given: s is the midpoint of rt
definition of midpoint: rs st
given: st xg
transitive property of congruence: rs xy
This is the only way I can think of this mathematically. This took a good 20 minutes for me. You need to guess and check. Like try 17 quarters, 50 nickels, and 37 dimes etc. until you get 11.00. My numbers are mathematically correct but we both know you cant have 18.909 quarters so. lol
Answer:
Quarters: 18.909
Nickels: 49.818
Dimes: 37.818
Somewhere around those numbers.
Step-by-step explanation:
$11.00 total in coins
Nickel = $0.05
Dime = $0.10
Quarter = $0.25
(n*0.05) + (d*0.10) + (q*0.25)
Solve the equation for q.
![q=\frac{1}{2} d](https://tex.z-dn.net/?f=q%3D%5Cfrac%7B1%7D%7B2%7D%20d)
(n*0.05) + (d*0.10) +(
*0.25)
Simplify the expression.
9d + 2n = 440
d - n = -12
Multiply both sides of the equation by -9.
-9d + 9n = 108
9d + 2n = 440
Sum the equations vertically to eliminate at least one variable.
11n = 548
![n=\frac{548}{11}](https://tex.z-dn.net/?f=n%3D%5Cfrac%7B548%7D%7B11%7D)
Substitute the given value of n into the equation d - n = -12
![d-\frac{548}{11} =-12](https://tex.z-dn.net/?f=d-%5Cfrac%7B548%7D%7B11%7D%20%3D-12)
![d=\frac{416}{11}](https://tex.z-dn.net/?f=d%3D%5Cfrac%7B416%7D%7B11%7D)
Substitute the given value of n into the equation ![q=\frac{1}{2} d](https://tex.z-dn.net/?f=q%3D%5Cfrac%7B1%7D%7B2%7D%20d)
![q=\frac{1}{2} *\frac{416}{11}](https://tex.z-dn.net/?f=q%3D%5Cfrac%7B1%7D%7B2%7D%20%2A%5Cfrac%7B416%7D%7B11%7D)
![q=\frac{208}{11}](https://tex.z-dn.net/?f=q%3D%5Cfrac%7B208%7D%7B11%7D)
Finally
d = 37.818
n = 49.818
q = 18.909
2x^-3= 2/x^3
you can't multiple 2x to the power of -3 because is not correct. so you need to change the equation for it to give you an answer
Answer:
https://www.jacksonsd.org/cms/lib/NJ01912744/Centricity/Domain/504/BI%207-8.pdf
Step-by-step explanation:
the link to help you with the answers
![\bf \textit{using the 2nd fundamental theorem of calculus}\\\\ \cfrac{dy}{dx}\displaystyle \left[ \int\limits_{0}^{x}\ cos^{-1}(t)dt \right]\implies cos^{-1}(x) \\\\\\ f'(0.3)\iff cos^{-1}(0.3)\approx 1.26610367277949911126](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Busing%20the%202nd%20fundamental%20theorem%20of%20calculus%7D%5C%5C%5C%5C%0A%5Ccfrac%7Bdy%7D%7Bdx%7D%5Cdisplaystyle%20%5Cleft%5B%20%5Cint%5Climits_%7B0%7D%5E%7Bx%7D%5C%20cos%5E%7B-1%7D%28t%29dt%20%5Cright%5D%5Cimplies%20cos%5E%7B-1%7D%28x%29%0A%5C%5C%5C%5C%5C%5C%0Af%27%280.3%29%5Ciff%20cos%5E%7B-1%7D%280.3%29%5Capprox%201.26610367277949911126)
now.. 0.3 is just a value...we'e assuming Radians for the inverse cosine, so, if you check, make sure your calculator is in Radian mode