Answer:
q = 7
Step-by-step explanation:
Given
18 - 2q = 4 ( Isolate the term in q by subtracting 18 from both sides )
- 2q = - 14 ( divide both sides by - 2 )
q =
= 7
Answer:
C
Step-by-step explanation:
Asymptote is basically a line that the graph approaches but NEVER cuts/crosses.
<em><u>Remember, x = a where a is a constant is an equation of a vertical line and x = b, where b is a constant, is the equation of a horizontal line.</u></em>
<em><u /></em>
- Looking at the graph, we can see that the curve doesn't cross an imaginary line at x = 0, this is a vertical asymptote.
- Also, we can see that the curve doesn't cross an imaginary line at y = -2, this is a horizontal asymptote.
Looking at the answer choices, the choice C is right.
Add positive 28 to get the sum 0
Answer:
80 and 40 are the other angles
Step-by-step explanation:
The simulation of the medicine and the bowler hat are illustrations of probability
- The probability that the medicine is effective on at least two is 0.767
- The probability that the medicine is effective on none is 0
- The probability that the bowler hits a headpin 4 out of 5 times is 0.3281
<h3>The probability that the medicine is effective on at least two</h3>
From the question,
- Numbers 1 to 7 represents the medicine being effective
- 0, 8 and 9 represents the medicine not being effective
From the simulation, 23 of the 30 randomly generated numbers show that the medicine is effective on at least two
So, the probability is:
p = 23/30
p = 0.767
Hence, the probability that the medicine is effective on at least two is 0.767
<h3>The probability that the medicine is effective on none</h3>
From the simulation, 0 of the 30 randomly generated numbers show that the medicine is effective on none
So, the probability is:
p = 0/30
p = 0
Hence, the probability that the medicine is effective on none is 0
<h3>The probability a bowler hits a headpin</h3>
The probability of hitting a headpin is:
p = 90%
The probability a bowler hits a headpin 4 out of 5 times is:
P(x) = nCx * p^x * (1 - p)^(n - x)
So, we have:
P(4) = 5C4 * (90%)^4 * (1 - 90%)^1
P(4) = 0.3281
Hence, the probability that the bowler hits a headpin 4 out of 5 times is 0.3281
Read more about probabilities at:
brainly.com/question/25870256