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Lubov Fominskaja [6]
3 years ago
10

Can u help me with this algebra question

Mathematics
1 answer:
pashok25 [27]3 years ago
6 0
The parent function for quadratic equations is as followed:

y=a(bx-h)^2+k

where a for vertical stretches, b is for horizontal stretches, h is the x value of the vertex, and k is the y value of the vertex.

The vertex of the is (-3, -2), so we can write the first part of the equation:

y=a(bx+3)^2-2

To determine if the graph has any stretches, we can check how changes to the x coordinate affect the y value. If there  are no stretches, as the x coordinate moves away from the vertex, the y coordinate should be x^2 from the vertex. If we test with a couple points on the graph, wee see that this is true, so there are no stretches. The answer is:

y=(x+3)^2-2


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WILL MARK BRAINIEST FOR FIRST PERSON TO ANSWER WITH THE STEPS
kondaur [170]

Answer:

  a. 1.2 ohms

  b. 6 ohms

Step-by-step explanation:

As with any problem involving evaluation of a formula, substitute the given values for the corresponding variables and do the arithmetic.

a.

  R=\dfrac{1}{\dfrac{1}{R_1}+\dfrac{1}{R_2}}=\dfrac{1}{\dfrac{1}{2}+\dfrac{1}{3}}=\dfrac{1}{\left(\dfrac{5}{6}\right)}=\boxed{\dfrac{6}{5}=1.2}

__

b.

  R=\dfrac{1}{\dfrac{1}{R_1}+\dfrac{1}{R_2}}=\dfrac{1}{\dfrac{1}{10}+\dfrac{1}{15}}=\dfrac{1}{\left(\dfrac{5}{30}\right)}=\dfrac{30}{5}=\boxed{6}

_____

<em>Comment on these problems</em>

You will notice that the values in part (b) are 5 times those in part (a). So, it is no surprise that the answer in part (b) is 5 times the answer in part (a).

7 0
3 years ago
PLZZZZZZZZZ ANSWER 25 thanks
cluponka [151]
C would be your answer

6 0
3 years ago
Read 2 more answers
In a sample of 42 burritos, we found a sample mean 1.4 lb and assumed that sigma equals.5. In a test of the hypothesis H subscri
Sergio [31]

Answer:

D. 0.9953 (Probability of a Type II error), 0.0047 (Power of the test)

Step-by-step explanation:

Let's first remember that a Type II error is to NOT reject H0 when it is false, and the probability of that occurring is known as β. On the other hand, power refers to the probability of rejecting H0 when it is false, so it can be calculated as 1 - β.

To resolve this we are going to use the Z-statistic:

                                           Z = (X¯ - μ0) / (σ/√n)

where  μ0 = 1.2

            σ = 5

            n = 42

As we can see in part A of the attached image, we have the normal distribution curve representation for this test, and because this is a two-tailed test, we split the significance level of α=0.01 evenly into the two tails, 0.005 in each tail, and if we look for the Z critical value for those values in a standard distribution Z table we will find that that value is 2.576.

Now we need to stablish the equation that will telll us for what values of X¯ will we reject H0.

Reject if:

Z ≤ -2.576                                                          Z ≥ 2.576

We know the equation for the Z-statistic, so we can substitute like follows and resolve.

Reject if:

(X¯ - 1.2) / (5/√42) ≤ -2.576                          (X¯ - 1.2) / (5/√42) ≥ 2.576

X¯ ≤ -0.79                                                         X¯ ≥ 3.19

We have the information that the true population mean is 1.25, so we now for a fact that H0 is false, so with this we can calculate the probability of a Type II error:  P(Do not reject H0 | μ=1.25)

As we can see in part B of the attached image, we can stablish that the type II error will represent the probability of the sample mean (X¯) falling between -0.79 and 3.19 when μ=1.25, and that represents the shaded area. So now we now that we are looking for P(-0.79 < X¯ < 3.19 | μ=1.25).

Because we know the equation of Z, we are going to standardize this as follows:

P ( (-0.79 - 1.25) / (5/√42) < Z <  (3.19 - 1.25) / (5/√42) )

This equals to:

P(-2.64 < Z < 2.51)

If we go and look for the area under the curve for Z positive scores in a normal standart table (part C of attached image), we will find that that area is 0.9940, which represents the probability of a Type II error.

Therefore, the power of the test will be 1-0.9940 = 0.006

If we look at the options of answers we have, there is no option that looks like this results, which means there was a probable redaction error, so we are going to stay with the closest option to these values which is option D.

3 0
3 years ago
We have five samples of data: sample A with 30 successes of 50 cases, sample B with 600 successes of 1000 cases, sample C with 3
faust18 [17]

Answer:

C. with 3000 successes of 5000 cases sample

Step-by-step explanation:

Given that we need to test if the proportion of success is greater than 0.5.

From the given options, we can see that they all have the same proportion which equals to;

Proportion p = 30/50 = 600/1000 = 0.6

p = 0.6

But we can notice that the number of samples in each case is different.

Test statistic z score can be calculated with the formula below;

z = (p^−po)/√{po(1−po)/n}

Where,

z= Test statistics

n = Sample size

po = Null hypothesized value

p^ = Observed proportion

Since all other variables are the same for all the cases except sample size, from the formula for the test statistics we can see that the higher the value of sample size (n) the higher the test statistics (z) and the highest z gives the strongest evidence for the alternative hypothesis. So the option with the highest sample size gives the strongest evidence for the alternative hypothesis.

Therefore, option C with sample size 5000 and proportion 0.6 has the highest sample size. Hence, option C gives the strongest evidence for the alternative hypothesis

3 0
3 years ago
Help... do it now if you can pls...
slavikrds [6]

Answer:

1.A,B,C,D

2. AB, CD

3. AC, BD

4. Line AD (don't take my word for this one)

Step-by-step explanation:

7 0
3 years ago
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