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Dmitrij [34]
3 years ago
13

At a Halloween fair, you see a huge Ferris wheel. There are ten seats on the wheel, with two people placed on each seat. Every m

inute, a seat passes by the exit platform. The Ferris wheel opened for 30 minutes at 11 a.m. and doubled its speed after fifteen minutes. How many people rode the wheel during this time?
This is just a fun question I need answered!
Mathematics
2 answers:
netineya [11]3 years ago
7 0

Answer:

answer

Step-by-step explanation:

steposvetlana [31]3 years ago
5 0
46 it’s just a random guess but if it’s right WOW
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Work out the shaded area of this shape.
Yuri [45]

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look at the picture .................

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Find the value of x and y in the parallelogram below
avanturin [10]

Answer:

y = 41

x = 64

Step-by-step explanation:

8 0
3 years ago
How do Solve These?????????
svlad2 [7]

Answer:

The slope of the parallel lines would be the same but the slope of the perpendicular lines would be the reciprocal

Step-by-step explanation:

To find a reciprocal for 1, 3, 4, 5, and 9 (whole numbers) just put a 1 over the number to make it a fraction and for 2, 6, 7, 8, and 10 (fractions) just flip it.

For example 1 would be 1/10 and 2 would be 3/2

8 0
4 years ago
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Multiply.<br> (x-6)(4x + 3)
d1i1m1o1n [39]

Answer:

Fully simplified it equals 4x^2 -21x -18

Explanation:

-You need to distribute the x to all of the terms in the second binomial and you also need to distribute -6 to all the terms in the second binommial giving you 4x^2 +3x - 24 -18

-You combine like terms to simplify and your answer is 4x^2 -21x -18

7 0
3 years ago
A grower believes that one in five of his citrus trees are infected with the citrus red mite. How large a sample should be taken
mihalych1998 [28]

Answer:

n=6147

Step-by-step explanation:

1) Notation and definitions

X=1 number of citrus trees that are infected with the citrus red mite.

n=5 random sample taken

\hat p=\frac{1}{5}=0.2 estimated proportion of citrus trees that are infected with the citrus red mite.

p true population proportion of citrus trees that are infected with the citrus red mite.

Me=0.01 represent the margin of error desired

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

In order to find the critical values we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical values would be given by:

t_{\alpha/2}=-1.96, t_{1-\alpha/2}=1.96

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.01 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.2(1-0.2)}{(\frac{0.01}{1.96})^2}=6146.56  

And rounded up we have that n=6147

5 0
4 years ago
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