I've already answered the question. So it is::
A is c and a because it's on the left of 0.
B is b and d because it's on the right of 0.
C is additive inverse.
-- The width of the school is ' W '. We don't know what that is yet,
but we're going to find out.
-- We're told that the length is 4 times as much. So the length is ' 4 W '.
-- Perimeter is (2 widths) + (2 lengths).
2 widths = 2 W
2 lengths = 8 W
Perimeter = 10 W
-- We're also told that the perimeter is 55m. That's just what we need.
10 W = 55 m
Divide each side of this equation by 10:
W = 5.5 m
There's the width !
The length of the hall is 4 times as much.
Length = 4 W = 22 m
<u>the correct question is</u>
The denarius was a unit of currency in ancient rome. Suppose it costs the roman government 10 denarii per day to support 4 legionaries and 4 archers. It only costs 5 denarii per day to support 2 legionaries and 2 archers. Use a system of linear equations in two variables. Can we solve for a unique cost for each soldier?
Let
x-------> the cost to support a legionary per day
y-------> the cost to support an archer per day
we know that
4x+4y=10 ---------> equation 1
2x+2y=5 ---------> equation 2
If you multiply equation 1 by 2
2*(2x+2y)=2*5-----------> 4x+4y=10
so
equation 1 and equation 2 are the same
The system has infinite solutions-------> Is a consistent dependent system
therefore
<u>the answer is</u>
We cannot solve for a unique cost for each soldier, because there are infinite solutions.
Answer:
80
Step-by-step explanation:
89^2-39^2=6400, 6400=80^2
