6 Paul runs 1.5 km on the bearing 127°. a Draw a diagram of the situation. b How far east is Paul from his starting point? ( How
1 answer:
By running in a bearing of 127°, Paul motion is in the south eastern direction.
Correct responses:
a. Please find attached the required diagram created with MS Visio
b. Paul's distance travelled east is approximately 11.98 km
- Paul's distance travelled south is approximately 0.903 km
Given:
The distance Paul runs = 1.5 km
The bearing Paul is running = 127°
a. The bearing of path Paul runs, 127°, is the angle measured in the clockwise direction relative to the northern direction
Please find attached the diagram representing the situation, created with MS Visio.
b. Paul's distance travelled east relative to the starting point is given by the component of Paul's path in the x-axis direction which is found as follows;
- Paul's distance east = 15 km × cos(37°) ≈ <u>11.98 km</u>
Pau's distance travelled in the south direction relative to the starting point
is given by the vertical distance travelled relative to the x-axis, which is
given as follows;
Distance Paul travels south = 1.5 km × sin(37°) ≈ <u>0.903 km</u>
Learn more about bearings in trigonometry here:
You might be interested in
Answer:
C. Those who have a car tend to have a cell phone.
Step-by-step explanation:
The relative frequency for a data set n is calculated by dividing each frequency by n.
We have a table that relates the use of cars and cell phones.
First, we take from the table the population that has a car.
Then, of the students who have a car, 12 have a cell phone and 6 do not have a cell phone.
Then we calculate the relative frequencies for those who have a cell phone and those who do not.
______________________________________________
Relative frequency Students with car n = 18.
-------------------------------------------------- --------------------------------------
C<em>ell phone No cell phone Total n</em>
12/18 6/18 18
_______________________________________________
_______________________________________________
Relative frequency Students with car n = 18.
-------------------------------------------------- --------------------------------------
C<em>ell phone No cell phone Total n</em>
0.666 0.333 18
________________________________________________
Most students who have a car also have a cell phone.
Now we calculate the relative frequency for students who do not have a car.
_______________________________________________
Relative frequency Students without a car n = 7
-------------------------------------------------- --------------------------------------
<em>Cell phone No cell phone Total n</em>
2/7 5/7 7
_______________________________________________
_______________________________________________
Relative frequency Students without a car n = 7
-------------------------------------------------- --------------------------------------
<em>Cell phone</em> <em> No</em> <em>cell phone Total n</em>
0.286 0.714 7
_______________________________________________
Most students who do not have a car do not have a cell phone either.
<em>Then these data suggest that. Those who have a car tend to have a cell phone.</em>
Option C