Ariel has 20 bouncy balls. He later then sold them for a price of $2 per ball to his best friend, Mike Hawk. Later, Ariel has go
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Let Daniel's age be 'x' years , hence, Lisa's age is (x - 5) years. Let Grandma's age be 'y' = 54 years.
Hence,
x(x - 5) = 2/3 × y
x² - 5x = 2 × 54 years / 3
x² - 5x = 36 years
x² - 5x - 36 = 0
∆ = (-5)² - 4(1)(-36) = 25 + 144 = 169
√∆ = √169 = 13
x1 = (5+13)/2, x2 = (5-13)/2
x1 = 9, x2 = -4
Since, age can't be negative,
Daniel's age = x = 9 years.
Hence,
x(x - 5) = 2/3 × y
x² - 5x = 2 × 54 years / 3
x² - 5x = 36 years
x² - 5x - 36 = 0
∆ = (-5)² - 4(1)(-36) = 25 + 144 = 169
√∆ = √169 = 13
x1 = (5+13)/2, x2 = (5-13)/2
x1 = 9, x2 = -4
Since, age can't be negative,
Daniel's age = x = 9 years.
The number of bins in the histogram determines the width of the bins and
the frequency (number of members) in a bin.
- Please find attached the graph of the histogram of Gretchen's data created with MS Excel.
Given:
The table from Gretchen's data is presented as follows;
The required number of bins = 8 bins
The steps to create the histogram using MS Excel;
- Enter the 15 dataset for the number of days as presented in the above table in a column on the worksheet.
- Select the dataset entered into the cells from above then select the Insert menu.
- In the Chart section of the insert menu click on the Histogram icon to view the quick options for histograms type charts.
- Select the Histogram option from the drop down menu from the quick options for histograms, to create an histogram chart.
- Right-click the histogram created from the previous step, then select Format Chart Area from the pop up menu.
- In the Format Chart Area task pane, click on the arrow next to Chart Options, then select Horizontal Axis from the options menu.
- Click on the histogram icon under Axis Options, then click on arrow button besides Axis Option sub menu, to display the axis options.
- Click on the Number of bins radio button then enter 8, to create an histogram having 8 bins.
The histogram of Gretchen's data having eight bins created with MS Excel is attached.
Learn more about creating a histogram chart here:
Answer:
0.0668 = 6.68% probability that an individual man’s step length is less than 1.9 feet.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Normally distributed with a mean of 2.5 feet and a standard deviation of 0.4 feet.
This means that
Find the probability that an individual man’s step length is less than 1.9 feet.
This is the p-value of Z when X = 1.9. So
has a p-value of 0.0668
0.0668 = 6.68% probability that an individual man’s step length is less than 1.9 feet.