Someone please help

One gallon of paint is equivalent to 3.78 liters.Michael wants to determine how many centiliters this is.Which answer choice is

Jet001 [13]

Answer:

378 cl

Step-by-step explanation

1L=100 cl

3.78 × 100= 378 cl

8 0

3 years ago

The FBI wants to determine the effectiveness of their 10 Most Wanted list. To do so, they need to find out the fraction of peopl

Zinaida [17]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is X: number of criminals in the 10 Most Wanted list that were captured in a sample of 523 suspected criminals.

The number of criminals that were captured is 172 out of 523.

To calculate the sample proportion, you have to divide the number of success, in this case, captured criminals, by the total number of criminals sampled:

^p= 172/523= 0.329

I hope this helps!

7 0

4 years ago

A recent study focused on the number of times men and women who live alone buy take-out dinner in a month. Assume that the distr

Marianna [84]

Answer:

(a) Decision rule for 0.01 significance level is that we will reject our null hypothesis if the test statistics does not lie between t = -2.651 and t = 2.651.

(b) The value of t test statistics is 1.890.

(c) We conclude that there is no difference in the mean number of times men and women order take-out dinners in a month.

(d) P-value of the test statistics is 0.0662.

Step-by-step explanation:

We are given that a recent study focused on the number of times men and women who live alone buy take-out dinner in a month.

Also, following information is given below;

Statistic : Men Women

The sample mean : 24.51 22.69

Sample standard deviation : 4.48 3.86

Sample size : 35 40

Let $\mu_1$ = mean number of times men order take-out dinners in a month.

$\mu_2$ = mean number of times women order take-out dinners in a month

(a) So, Null Hypothesis, $H_0$ : $\mu_1-\mu_2$ = 0 {means that there is no difference in the mean number of times men and women order take-out dinners in a month}

Alternate Hypothesis, $H_A$ : $\mu_1-\mu_2\neq$ 0 {means that there is difference in the mean number of times men and women order take-out dinners in a month}

The test statistics that would be used here Two-sample t test statistics as we don't know about the population standard deviation;

T.S. = $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ~ $t__n_1_-_n_2_-_2$

where, $\bar X_1$ = sample mean for men = 24.51

$\bar X_2$ = sample mean for women = 22.69

$s_1$ = sample standard deviation for men = 4.48

$s_2$ = sample standard deviation for women = 3.86

$n_1$ = sample of men = 35

$n_2$ = sample of women = 40

Also, $s_p=\sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2} }{n_1+n_2-2} }$ = $\sqrt{\frac{(35-1)\times 4.48^{2}+(40-1)\times 3.86^{2} }{35+40-2} }$ = 4.16

So, test statistics = $\frac{(24.51-22.69)-(0)}{4.16 \sqrt{\frac{1}{35}+\frac{1}{40} } }$ ~ $t_7_3$

= 1.890

(b) The value of t test statistics is 1.890.

(c) Now, at 0.01 significance level the t table gives critical values of -2.651 and 2.651 at 73 degree of freedom for two-tailed test.

Since our test statistics lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that there is no difference in the mean number of times men and women order take-out dinners in a month.

(d) Now, the P-value of the test statistics is given by;

P-value = P( $t_7_3$ > 1.89) = 0.0331

So, P-value for two tailed test is = 2 $\times$ 0.0331 = 0.0662

4 0

3 years ago

Eight less than four times a number is less than 56.What are the possible values of that number

Gemiola [76]

We have the next inequation
8-4x<56

-4x<56-8
-4x<48
-x<48/4
-x<12
x>-12

Solution: x>-12 or (-12,+∞)

4 0

4 years ago

In many parades, flowers are used to decorate the floats. The table below shows the number of flowers used in each row of a para

inessss [21]

Answer: C. n = 4r + 50

Step-by-step explanation:

The equation is in the form: y =mx + c

y is the number of flowers used.

x is the row number.

Solving for m. Pick any two points. (1, 54) and (2, 58)

m = (Y₂ - Y₁) / (X₂ - X₁)

= (58 - 54) / (2 - 1)

= 4

Solving for c. Use a point to fill up the formula and find c; (1, 54)

y = mx + c

54 = 4 * 1 + c

c = 54 - 4

c = 50

Formula will therefore be;

y = 4x + 50

or;

n = 4r + 50

5 0

3 years ago