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Zielflug [23.3K]
3 years ago
14

Kevin can travel 22.50 miles in 0.3. What is his average speed in miles per hour?

Mathematics
1 answer:
weeeeeb [17]3 years ago
7 0
His average speed will be 75 miles per hour. Hope it help!
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y = −2x+14

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Can you help me on my homework plz ​
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The vector v⃗ in 2-space of length 3 pointing up at an angle of π/4 measured from the positive x-axis.
allsm [11]

The vector v in 2-space of length 3 pointing up at an angle of π/4 measured from the positive x-axis is: (3/√2, 3√2) and The vector w in 3-space of length 1 lying in the yz-plane pointing upward at an angle of 2π/3 measured from the positive y-axis is: (0, -1/2, √3/2).

<h3>Vector</h3>

a. Vector (v)

Vector (v)=v (cos Ф, sin Ф)

V=1 while the counterclockwise angle that is measured from positive x=Ф=π/4

Hence:

Vector=3(cos π/4, sinπ/4)

Vector=(3/√2, 3√2)

b. Vector w:

Vector w=1(0, cos 2π/3, sin2π/3)

Vector w=(0, -1/2, √3/2)

Therefore the vector v in 2-space of length 3 pointing up at an angle of π/4 measured from the positive x-axis is: (3/√2, 3√2) and The vector ws: (0, -1/2, √3/2).

The complete question is:

Resolve the following vectors into components:

a. The vector v in 2-space of length 3 pointing up at an angle of π/4 measured from the positive x-axis.

(b) The vector w in 3-space of length 1 lying in the yz-plane pointing upward at an angle of 2π/3 measured from the positive y-axis.

Learn more about vector here:brainly.com/question/25705666

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1 year ago
How do you write 6,007,200 in words
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3 0
3 years ago
Read 2 more answers
you want to create a 99 confidence interval with a margin of error of 25 assuming that the population standard deviation is equa
Ahat [919]

Answer:

The minimum sample size is 239.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.99}{2} = 0.005

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.005 = 0.995, so Z = 2.575.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

Population standard deviation is equal to 1.5

This means that \sigma = 1.5

Margin of error of 0.25

This means that M = 0.25

What's the minimum size of the sample?

M = z\frac{\sigma}{\sqrt{n}}

0.25 = 2.575\frac{1.5}{\sqrt{n}}

0.25\sqrt{n} = 2.575*1.5

\sqrt{n} = \frac{2.575*1.5}{0.25}

(\sqrt{n})^2 = (\frac{2.575*1.5}{0.25})^2

n = 238.7

Rounding up:

The minimum sample size is 239.

4 0
3 years ago
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