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2 years ago

−3x^ 4−7x+17=0

Mathematics

1 answer:

Trava [24]2 years ago

8 0

There are 4. if the equation ax^2 +bx +c=0 has 2 roots, then x^4 has 4.

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Add 1 1/3+(−5/6) <br><br> brainliest given to the right answer

4vir4ik [10]

1 and 1/3 is 3/3 and 1/3 so is 4/3 then

4/3 -5/6 they have to have the same denominators so multiply the first fraction with 2/2

(4•2/3•2)-5/6=(8/6)-(5/6)= (8-5)/6=3/6 that you can simplify as 1/2

4 0

3 years ago

Read 2 more answers

A ladder leans against a wall 6 ft above the ground. The base of the ladder is 3 ft from the wall. How long is the ladder?

Igoryamba

Answer:

6.71

Step-by-step explanation:

Hopefully this helps! :)

7 0

2 years ago

Help plese I hope the pic works

Ivan

A=100
b=8
w=108
756 divided by 7=108

6 0

2 years ago

I’m not sure of how to do this. Pls help

Semmy [17]

Just divide. 3/4 is 3 divided by 4= .75
75 hundredths is the same as 75%
20/100 20 divided by 100=.20 which is 20%
14 divided by 25 is .56, or 56%
1/5 is 1 divided by 5 = .20 or 20 %

3 0

2 years ago

The standard deviation for actuary salaries has a standard deviation of $36,730 . You collect a simple random sample of n=36 sal

Yanka [14]

Using the z-distribution, it is found that the lower limit of the 95% confidence interval is of $99,002.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

$\overline{x} \pm z\frac{\sigma}{\sqrt{n}}$

In which:

$\overline{x}$ is the sample mean.

z is the critical value.

n is the sample size.

$\sigma$ is the standard deviation for the population.

In this problem, we have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96.

The other parameters are given as follows:

$\overline{x} = 111000, \sigma = 36730, n = 36$

Hence, the lower bound of the interval is:

$\overline{x} - z\frac{\sigma}{\sqrt{n}} = 111000 - 1.96\frac{36730}{\sqrt{36}} = 99002$

The lower limit of the 95% confidence interval is of $99,002.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

8 0

1 year ago