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Colt1911 [192]
2 years ago
14

\ \textgreater \ 0" alt="5x^{2}+|x+1|\ \textgreater \ 0" align="absmiddle" class="latex-formula">
Can someone explain me how this is done? My book says that the answer is R (all numbers), but i get [-1; infinity) and two other roots.
Mathematics
1 answer:
Pavel [41]2 years ago
7 0
5x² + |x+1| > 0
5x² + x + 1 > 0
x+1 > 0 because it came from absolute
5x² > 0 because it’s squared

When you try a number you should put it in the original equality
5x² + |x+1|
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<em>Answer</em><em> </em><em>is</em><em> </em><em>x</em><em>=</em><em>52</em><em>.</em><em>12</em>

<em>approximately</em><em> </em><em>equals</em><em> </em><em>to</em><em> </em><em>52</em><em> </em><em>degrees</em><em>. </em>

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\tan( \alpha )  =  \frac{9}{7}  \\ to \: find \:  \alpha  \\ therefore \alpha  =   { \tan}^{ - 1}  \frac{9}{7}  \\

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<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

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